Answer:
Explanation:
Translate every verbal statement into an algebraic statement,
<u>1. Keith has $500 in a savings account at the beginning of the summer.</u>
<u>2. He wants to have at least $200 in the account by the end of summer. </u>
<u />
<u>3. He withdraws $25 a week for his cell phone bill.</u>
<u />
- Call w the number of weeks
<u>4. Write an inequality that represents Keith's situation.</u>
- Create your model: Final amount = Initial amount - withdrawals ≥ 500
With that inequality you can calculate how many week will pass before his account has less than the amount he wants to have in the account by the end of summer:
That represents that he can afford spending $ 25 a week during 12 weeks to have at least $ 200 in the account.
Answer:

Step-by-step explanation:
This scenario can be modeled using an exponential growth equation.
The exponential growth equations have the following form:

Where P is the population in year t
p is the initial population at t = 0
r is the growth rate
t is the time in years.
In this case we know that the current population is 13,000 and that the growth rate is 11%
So

The equation that models this scenario is:


Answer:
company B
Step-by-step explanation:
the company is good!
I’m here to help.
For this question here you need to use the sine formula for the area of a triangle and figure out the area of the sector
I’ll take you through it step-by-step
Area of the arc:
We only have 68.9 degrees out of 360 and we need to use the formula for the area of a circle.
Formula of a circle = pi x radius squared
68.9/360 x pi x 86.1184= 51.78 (2dp)
Area of triangle:
As you can see we have no height so we must use the sine formula for the area of a triangle.
Formula= 1/2abSinC
You should end up with
0.5 x 9.28x 9.28 x Sin(68.9)= 40.17 (2dp)
Now since you want the area of the segment shaded, just find the difference between these two values.
51.78-40.17 = 11.61
Answer= 11.6cm squared
Hope this helped!
Problem
For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground
Solution
We know that the x coordinate of a quadratic function is given by:
Vx= -b/2a
And the y coordinate correspond to the maximum value of y.
Then the best options are C and D but the best option is:
D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a
The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.