Answer:
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
Step-by-step explanation:
Given that;
the frequencies of there alternatives are;
Frequency A = 60
Frequency B = 12
Frequency C = 48
Total = 60 + 12 + 48 = 120
Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;
Relative Frequency A = Frequency A / total = 60 / 120 = 0.5
Relative Frequency B = Frequency B / total = 12 / 120 = 0.1
Relative Frequency C = Frequency C / total = 48 / 120 = 0.4
therefore;
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
He need to earn 48
Inequality : 80-32=x
Answer:
<h2>The answer is option C</h2>
Step-by-step explanation:
<h3>

</h3>
Using the rules of indices
Since the bases are the same and are dividing we subtract the exponents
That's
<h3>

</h3>
So we have
<h3>

</h3>
Using the rules of indices
<h3>

</h3>
So we have the final answer as
<h2>

</h2>
Hope this helps you
Answer:
the second option
Step-by-step explanation:
in ax²+bx+c = 0:

subtract both sides by 6 to get to this form, as the right side will be left with 0
6x² + 8x - 6 = 0
here, the coefficient for x² (a) is 6, the coefficient for x (b) is 8, and the remaining number added on (c) is -6
plugging our numbers into the formula, we get
