Question

What is the value halp me​

Answer 1

Answer:

$g\left(1\right)=-\frac{1}{5}$

Step-by-step explanation:

Given

Let the function

$g\left(x\right)=\frac{x^2-3}{10}$

To determine

g(1) = ?

Given the function

$g\left(x\right)=\frac{x^2-3}{10}$

substitute x = 1

$g\left(1\right)=\frac{\left(1\right)^2-3}{10}$

        $=\frac{\left(1\right)^2-3}{10}$

        $=\frac{1-3}{10}$

         $=\frac{-2}{10}$

         $=-\frac{2}{10}$

         $=-\frac{1}{5}$

Therefore,

$g\left(1\right)=-\frac{1}{5}$