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arlik [135]
3 years ago
7

Xt-3=y solve the literal equation for the variable T.

Mathematics
1 answer:
faltersainse [42]3 years ago
5 0
Xt-3=y

Move three to the other side as a positive number

xt=3+y

Divide everything by x

t=3+y divided by x
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The point P(5,1) lies on the curve y=5x. If Q is the point (x,5x), find the slope of the secant line PQ for the following values
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Answer:

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Step-by-step explanation:

We have been given that the point P(1,5) lies on the curve y=5x. Q is the point (x,5x). We are asked to find the slope of the secant line PQ for x=5.1.

Let us find y-coordinate corresponding to x=5.1 for point P as:

y=5(5.1)=25.5

Now, we will use slope formula to find required slope.

m=\frac{y_2-y_1}{x_2-x_1}  

Let point (1,5)=(x_1,y_1) and point (5.1,25.5)=(x_2,y_2).

Using these points in slope formula, we will get:

m_{PQ}=\frac{25.5-5}{5.1-1}=\frac{20.5}{4.1}=5

Therefore, the slope of the line PQ is 5.  

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4 years ago
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