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3 years ago

1 point What is 20% of 60? Type your answer...

Mathematics

2 answers:

Lilit [14]3 years ago

8 0

Answer: 12

Step-by-step explanation:

alekssr [168]3 years ago

7 0

Answer:12

60×.20= 12

I hope this is good enough:

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Verify the identity: (1-sinx)/cosx = cosx/(1+sinx)

Tresset [83]

Cross multiply the expression so that we can get

(1+sinx)(1-sinx) = cos^2 x

1 - sin^2 x = cos^2 x

cos^2 x + sin^2 x = 1

since

cos^2 x + sin^2 x = 1

therefore

1 = 1

the two expressions are identical in a trigonometric sense

4 0

3 years ago

In Exercises 45–48, let f(x) = (x - 2)2 + 1. Match the function with its graph

MA_775_DIABLO [31]

Answer:

45) The function corresponds to graph A

46) The function corresponds to graph C

47) The function corresponds to graph B

48) The function corresponds to graph D

Step-by-step explanation:

We know that the function f(x) is:

$f(x)=(x-2)^{2}+1$

45)

The function g(x) is given by:

$g(x)=f(x-1)$

using f(x) we can find f(x-1)

$g(x)=((x-1)-2)^{2}+1=(x-3)^{2}+1$

If we take the derivative and equal to zero we will find the minimum value of the parabolla (x,y) and then find the correct graph.

$g(x)'=2(x-3)$

$2(x-3)=0$

$x=3$

Puting it on g(x) we will get y value.

$y=g(3)=(3-3)^{2}+1$

$y=g(3)=1$

Then, the minimum point of this function is (3,1) and it corresponds to (A)

46)

Let's use the same method here.

$g(x)=f(x+2)$

$g(x)=((x+2)-2)^{2}+1$

$g(x)=(x)^{2}+1$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2x$

$0=2x$

$x=0$

Evaluatinf g(x) at this value of x we have:

$g(0)=(x)^{2}+1$

$g(0)=1$

Then, the minimum point of this function is (0,1) and it corresponds to (C)

47)

Let's use the same method here.

$g(x)=f(x)+2$

$g(x)=(x-2)^{2}+1+2$

$g(x)=(x-2)^{2}+3$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}+3$

$g(2)=3$

Then, the minimum point of this function is (2,3) and it corresponds to (B)

48)

Let's use the same method here.

$g(x)=f(x)-3$

$g(x)=(x-2)^{2}+1-3$

$g(x)=(x-2)^{2}-2$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}-2$

$g(2)=-2$

Then, the minimum point of this function is (2,-2) and it corresponds to (D)

I hope it helps you!

8 0

3 years ago

Darius had 1/2 an inch of hair cut off. Anna had 3/4 an inch of hair cut off. Penelope had 5/8 an inch of hair cut off. Who had

Anestetic [448]

I don’t know I just need points

4 0

2 years ago

Read 2 more answers

Can someone solve number 22 step by step?

Nana76 [90]

Answer:

2/3

Step-by -step explanation:

5 0

3 years ago

This question please i need help

grin007 [14]

Answer: the picture has no answer it's invalid but I will try:

X is a 90 degree angle other than that I can't do anything

Step-by-step explanation:

6 0

3 years ago

1 point What is 20% of 60? Type your answer...​

1 point What is 20% of 60? Type your answer...