
We have 2 denominators that we need to get rid of. Whenever there are the denominators, all we have to do is multiply all whole equation with the denominators.
Our denominators are both 2 and x+1. Therefore, we multiply the whole equation by 2(x+1)
![\frac{x}{2}[2(x+1)]-\frac{2}{x+1}[2(x+1)] = 1[2(x+1)]](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B2%7D%5B2%28x%2B1%29%5D-%5Cfrac%7B2%7D%7Bx%2B1%7D%5B2%28x%2B1%29%5D%20%3D%201%5B2%28x%2B1%29%5D)
Then shorten the fractions.
![\frac{x}{2}[2(x+1)]-\frac{2}{x+1}[2(x+1)] = 1[2(x+1)]\\x(x+1)-2(2)=1(2x+2)](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B2%7D%5B2%28x%2B1%29%5D-%5Cfrac%7B2%7D%7Bx%2B1%7D%5B2%28x%2B1%29%5D%20%3D%201%5B2%28x%2B1%29%5D%5C%5Cx%28x%2B1%29-2%282%29%3D1%282x%2B2%29)
Distribute in all.

We should get like this. Because the polynomial is 2-degree, I'd suggest you to move all terms to one place. Therefore, moving 2x+2 to another side and subtract.

We are almost there. All we have to do is, solving for x by factoring. (Although there are more than just factoring but factoring this polynomial is faster.)

Thus, the answer is x = 3, -2
Answer:
5. Inequality form: n ≥ 3
Interval notation: [3, ∞)
6. Inequality form: x < 4
Interval notation: (- ∞, 4)
11. Inequality form: x > 50
Interval notation: (50, ∞)
12. Inequality form: y
8
Interval notation: [8, ∞)
15. Inequality form: z < 8
Interval notation: (- ∞, 8)
16. Inequality form: y
4
Interval notation: [4, ∞)
Step-by-step explanation:
I tried to graph them as best as I could, I hope this helps!
Answer: 6
Step-by-step explanation:
Answer:
85%
Step-by-step explanation:
85% because I searched and it gave me 85%
Answer:

Step-by-step explanation:

To get
you needed to divide the numerator and denominator by 3.