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klasskru [66]
3 years ago
14

HeLlO I nEED aN ANsSWER aSap

Mathematics
1 answer:
nignag [31]3 years ago
6 0
What are the answer choices
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Sedbober [7]

Answer: The Earth makes one rotation every day.

Step-by-step explanation:

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Determine the domain of the function. (2 points) f as a function of x is equal to the square root of eleven minus x.
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f(x)=\sqrt{11-x}\\\\
D:11-x\geq0\\
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3 years ago
Consider the linear equation x- 3/2y = 2
Allisa [31]

Answer:

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Step-by-step explanation:

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Given the sequence -2,-8/3,-10/3,-4,-14/3 find the recursive formula
balu736 [363]

Step-by-step explanation:

-2, -8/3, -10/3, -4, -14/3

Write as multiples of 1/3.

-6/3, -8/3, -10/3, -12/3, -14/3

This is an arithmetic sequence where the first term is -6/3 and the common difference is -2/3.

Therefore, the recursive formula is:

aᵢ₊₁ = aᵢ − 2/3, a₁ = -2

3 0
3 years ago
Clarinex is a drug used to treat asthma. In clinical tests of this drug, 1655 patients were treated with 5- mg doses of Clarinex
bagirrra123 [75]

Answer:

z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363  

p_v =P(z>3.363)=0.00039  

So the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

Step-by-step explanation:

Data given and notation

n=1655 represent the random sample taken

\hat p=0.021 estimated proportion of interest

p_o=0.012 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that true proportions is higher than 0.012.:  

Null hypothesis:p \leq 0.012  

Alternative hypothesis:p > 0.012  

When we conduct a proportion test we need to use the z statisitic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>3.363)=0.00039  

So the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

3 0
3 years ago
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