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ikadub [295]
3 years ago
5

Need help with all these questions.

Mathematics
1 answer:
m_a_m_a [10]3 years ago
3 0
A. |x-3| - 2;
-5 - 3 = -8
Since we're doing absolute value, it'd be 8.
8 - 2 = 6

B. 1.5 x 0.2 = 0.3 (Just plug in the x value).

C. |7-2(-3)|
2 x -3 = -6
-6 + 7 = 1
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What is the solution of the system? Use substitution.
nekit [7.7K]
Substituting y=6x+2 into equation 3y - 18x =12 looks like:

3(6x + 2) - 18x = 12
18x + 6 - 18x = 12  distributive property left side
6 = 12  simplifying the left side

We now see a contradiction:   6 does not equal 12  What this tells us is that there is no solutions to this equation.  So choice 'C' ...
8 0
3 years ago
Read 2 more answers
A graph is given below. Answer the following questions based off the graph:
Tcecarenko [31]

(a) The slope of the graph is \frac{2}{5}

(b) The equation of the line in point-slope form is y - 1 = \frac{2}{5} (x + 2.5)

(c) The y-intercept of the graph is (0 , 2)

(d) The y-intercept is correct

(e) We substitute x by zero because the line intersects y-axis at a point

its x-coordinate must be zero. Then we calculate the value of

y-coordinate when x = 0. The y-coordinate = 2, so the

y-intercept is (0 , 2)

Step-by-step explanation:

The slope of a line whose endpoints are (x_{1},y_{1}) and (x_{2},y_{2})

is m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

The equation of a line in a point-slope form is:

y-y_{1}=m(x-x_{1})

From the graph:

1. The line passes through points (-5 , 0) and (0 , 2)

2. Substitute these points in the rule of the slope to find it

3. Writ the equation of the line in the form of point-slope

(a)

∵ (x_{1},y_{1}) = (-5 , 0)

∵ (x_{2},y_{2}) = (0 , 2)

∴ m=\frac{(2-0)}{(0--5)}=\frac{2}{5}

The slope of the graph is \frac{2}{5}

(b)

∵ Point (-2.5 , 1) lies on the line

∴ (x_{1},y_{1}) = (-2.5 , 1)

∵ The point-slope form is ⇒ y-y_{1}=m(x-x_{1})

∵ m = \frac{2}{5}

- Substitute the coordinates of the point and the slope in the equation

∴ y - 1 = \frac{2}{5} (x - -2.5)

∴ y - 1 = \frac{2}{5} (x + 2.5)

The equation of the line in point-slope form is y - 1 = \frac{2}{5} (x + 2.5)

(c)

When the line intersects the y-axis at point (0 , b), then b is the

y-intercept

∵ The line intersects y-axis at point (0 , 2)

∴ The y-intercept is (0 , 2)

The y-intercept of the graph is (0 , 2)

(d)

Let us substitute x in the equation by zero

∵ x = 0

∵ The point slope form of the equation is y - 1 = \frac{2}{5} (x + 2.5)

∴ y - 1 = \frac{2}{5} (0 + 2.5)

∴ y - 1 = \frac{2}{5} (2.5)

∴ y - 1 = 1

- Add 1 to both sides

∴ y = 2

- When x = 0 then y = 2

∴ Point (0 , 2) is the y-intercept

The y-intercept is correct

(e)

We substitute x by zero because the line intersects y-axis at a point its

x-coordinate must be zero

Then we calculate the value of y-coordinate when x = 0

The y-coordinate = 2, so the y intercept is (0 , 2)

Learn more:

You can learn more about linear equation in brainly.com/question/13168205

#LearnwithBrainly

6 0
4 years ago
Which quadratic equation has the roots -1+4i and -1-4i
AysviL [449]

Answer:

C

Step-by-step explanation:

Solve the quadratic in answer choice C using the quadratic formula:

x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}.

Here a=1, b=2, and c=17.

Substitute and you'll have:

x=\frac{-b+/-\sqrt{b^2-4ac} }{2a} =\frac{-2+/-\sqrt{(-2)^2-4(1)(17)} }{2(1)}=\frac{-2+/-\sqrt{4-68}}{2)}

\frac{-2+/-\sqrt{-64} }{2}=\frac{-2+/-8i }{2}=-1+/- 4i


6 0
4 years ago
In your class seven students do not receive a weekly allowance, Five students receive three dollars, Seven students receive five
olya-2409 [2.1K]

Answer:

\large \boxed{\text{\$3.50}}

Step-by-step explanation:

The mean is the sum of the allowances divided by the number of students.

\text{Mean}= \dfrac{7(0) + 5(3) + 7(5) + 3(6) + 2(8)}{24}= \dfrac{0 + 15 + 35 + 18 + 16}{24} = \mathbf{3.50}\\\text{The mean weekly allowance is $\large \boxed{\textbf{\$3.50}}$}

4 0
3 years ago
Two lines, A and B, are represented by the following equations:
almond37 [142]

Answer:

D.

Step-by-step explanation:

The solution is where the lines intersect which is at the point (3,2).

So the answer is Option D.

The point (3,2) satisfies both equations.

4 0
4 years ago
Read 2 more answers
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