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2 years ago

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which qaudratic equation is equivalent to (x+2)^2+5(x+2)-6=0 a. (u+2)^2+5(u+2)-6=0 where u=(x-2) b. u^2+4+5u-6=0 where u= (x-2)

c. u^2+5u-6=0 where u=(x+2) d. u^2+u-6=0 where u=(x+2)

1 answer:

Lisa [10]2 years ago

5 0

Answer:

D

Step-by-step explanation:

Given

(x + 2)² + 5(x + 2) - 6 = 0

Using the substitution u = x + 2 , then the equation can be expressed as

u² + 5u - 6 = 0 → D

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Answer:

Mean = 15.15

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Step-by-step explanation:

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2 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

In a standard deck of 52 playing cards, what is the complement (not below 8)?

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There are 8 card that fit the question (4 each of access and kings).

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2 years ago

Use the Pythagorean Theorem to determine which of the following give the measures of the legs and hypotenuse of a right triangle

kakasveta [241]

The Pythagorean theorem states that the square of the hypotenuse is equal to the sum of the squares of the legs:

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1. c=5, a=3, b=4:

$5^2=25,\\3^2+4^2=9+16=25,\\5^2=3^2+4^2$ true.

2. c=14, a=4, b=11:

$14^2=196,\\4^2+11^2=16+121=137,\\14^2\neq 4^2+11^2$ false.

3. c=17, a=9, b=14:

$17^2=289,\\9^2+14^2=81+196=277,\\17^2\neq 9^2+14^2$ false.

4. c=16, a=8, b=14:

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Answer: correct options are A and E.

4 0

2 years ago

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