Question

which qaudratic equation is equivalent to (x+2)^2+5(x+2)-6=0 a. (u+2)^2+5(u+2)-6=0 where u=(x-2) b. u^2+4+5u-6=0 where u= (x-2) c. u^2+5u-6=0 where u=(x+2) d. u^2+u-6=0 where u=(x+2)​

Answer 1

Answer:

D

Step-by-step explanation:

Given

(x + 2)² + 5(x + 2) - 6 = 0

Using the substitution u = x + 2 , then the equation can be expressed as

u² + 5u - 6 = 0 → D