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shepuryov [24]
3 years ago
5

which qaudratic equation is equivalent to (x+2)^2+5(x+2)-6=0 a. (u+2)^2+5(u+2)-6=0 where u=(x-2) b. u^2+4+5u-6=0 where u= (x-2)

c. u^2+5u-6=0 where u=(x+2) d. u^2+u-6=0 where u=(x+2)​
Mathematics
1 answer:
Lisa [10]3 years ago
5 0

Answer:

D

Step-by-step explanation:

Given

(x + 2)² + 5(x + 2) - 6 = 0

Using the substitution u = x + 2 , then the equation can be expressed as

u² + 5u - 6 = 0 → D

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There are x number of students at helms. If the number of students increases by 7.8% each year, how many students will be there
vodomira [7]

There will be 1.078x students next year and equation is number of students in next year = x + 7.8% of x

<h3><u>Solution:</u></h3>

Given, There are "x" number of students at helms.  

The number of students increases by 7.8% each year which means if there "x" number of students in present year, then the number of students in next year will be x + 7.8% of x

Number of students in next year = number of students in present year + increased number of students.

\begin{array}{l}{\text { Number of students in next year }=x+7.8 \% \text { of } x} \\\\ {\text { Number of students in next year }=x\left(1+\frac{7.8}{100}\right)} \\\\ {\text { Number of students in next year }=x(1+0.078)=1.078 x}\end{array}

Thus there will be 1.078x students in next year

3 0
3 years ago
Help with this one because I do not know how to do perpendicular plz put explanation with steps worth 50!
Yuri [45]

Answer:

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line 2x-3y=12 is 3x+2y=34  

Step-by-step explanation:

Given:  

2x-3y=12  

To Find:  

Equation of line passing through ( 16, -7) and is perpendicular to the line  

2x-3y=12  

Solution:  

2x-3y=12 ...........Given  

\therefore y=\dfrac{2}{3}\times x-4

Comparing with,  

y=mx+c  

Where m =slope  

We get  

Slope = m1 = \dfrac{2}{3}  

We know that for Perpendicular lines have product slopes = -1.

m1\times m2=-1

Substituting m1 we get m2 as

\dfrac{2}{3}\times m2=-1\\\\m2=-\dfrac{3}{2}

Therefore the slope of the required line passing through (16 , -7) will have the slope,

m2=-\dfrac{3}{2}  

Now the equation of line in slope point form given by  

(y-y_{1})=m(x-x_{1})  

Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,  

(y-(-7))=-\dfrac{3}{2}\times (x-16)\\\\2y+14=-3x+48\\3x+2y=34......Equation\ of\ line  

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line  2x-3y=12 is

3x+2y=34  

3 0
3 years ago
jack obtains a loan of $4815.16 at 2.3% ordinary interest for 42 days. what is the maturity value of the loan
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The maturity value is 4827 and if needed interest value is 12.
4 0
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Jada had read 2/3 of a book . She has read 60 pages so far . How many pages are in the whole book?
user100 [1]
90 pages in the whole book
3 0
3 years ago
On Monday, the high was 60oF. On Tuesday, the high was 10% more than Monday. Then on Wednesday, the temperature decrease by 8%.
Arada [10]

Answer:

60.72

Step-by-step explanation:

Monday: 60 degrees

Tuesday: temperature increases by 10 percent

60 + 10% of 60

60 + .10*60 = 70 +6 = 66

Wednesday: temperature decreases by 8 percent

66 - 8%of 66

66 - .08*66 = 66 -5.28=60.72

7 0
3 years ago
Read 2 more answers
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