which qaudratic equation is equivalent to (x+2)^2+5(x+2)-6=0 a. (u+2)^2+5(u+2)-6=0 where u=(x-2) b. u^2+4+5u-6=0 where u= (x-2)
c. u^2+5u-6=0 where u=(x+2) d. u^2+u-6=0 where u=(x+2)
1 answer:
Answer:
D
Step-by-step explanation:
Given
(x + 2)² + 5(x + 2) - 6 = 0
Using the substitution u = x + 2 , then the equation can be expressed as
u² + 5u - 6 = 0 → D
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