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Katen [24]
3 years ago
5

Hiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii iiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii iiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii iiiiiiiiiiiiiiiiiiiiiiii

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Please give me brainly
Mathematics
2 answers:
Levart [38]3 years ago
5 0

Answer:

HIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIiiiiiiiiiiiiiiiiiiiiiiiiIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii

Tamiku [17]3 years ago
5 0

Answer:

Please don't spam.

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Please help Bsbsn’s x
kaheart [24]

Answer:

  B.  a ⊥ d

Step-by-step explanation:

If lines "a" and "d" are in the same plane, they are perpendicular to each other. If not, there is no relationship between the lines.

__

Lines parallel to the same line are parallel to each other, so a║c. <em>In the same plane</em>, a line perpendicular to one of two parallel lines is also perpendicular to the other. (For example, one side of a rectangle is perpendicular to both of the adjacent sides, which are parallel to each other.)

The appropriate choice is ...

  a ⊥ d

__

<em>In 3 dimensions, ...</em>

Consider a cube. A given edge will be perpendicular to both of the two edges it meets at a corner.

It will not intersect (has no "perpendicular" relationship to) either of the edges parallel to those that meet at the corner at the other end of the space diagonal.

5 0
3 years ago
Tony wants to purchase a baseball glove for $14.96, a baseball bat for $19.87, and a baseball for $5.37. He figured out that he
Vanyuwa [196]
Reasonable because the three items altogether cost about $40
8 0
4 years ago
The midpoint of AB is M(-1, –4). If the coordinates of A are (-3, -7), what are
quester [9]

Answer:

<h3>            B(1, -1)</h3>

Step-by-step explanation:

If M(-1, 4) is midpoint of AB then:

x_M-x_A=x_B - x_M\qquad\quad\ \wedge\qquad y_M-y_A=y_B - y_M\\\\ -1-(-3)=x_B-(-1)\qquad\wedge\qquad -4-(-7)=y_B -(-4)\\\\ -1+3=x_B+1\qquad\qquad\wedge\qquad\ \ -4+7=y_B+4 \\\\ {}\qquad x_B=1\qquad\qquad\wedge\qquad\qquad \ y_B=-1

5 0
3 years ago
Find the value of the expression 4a4 − 2b2 + 40 when a = 2 and b = 7.
fiasKO [112]
4(2)^4 - 2(7^2) + 40
4(16)-2(49)+40
64 - 98 + 40
-34 + 40
= 6
6 0
3 years ago
Write a polynomial function with the given zeros. multiply the terms (write in standard form).
ryzh [129]

1) \ f(x)=x^3-3x-2 \\ \\ 2) \ g(x)=x^3-x^2-6x

<h2>Explanation:</h2>

A \ \mathbf{polynomial \ function} \ of \ x \ with \ degree \ n \ is \ given \ by:\\ \\ f(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\ldots +a_{2}x^{2}+a_{1}x+a_{0} \\ \\ where \ n \ is \ a \ nonnegative \ integer \ and \ a_{n}, a_{n-1}, \ldots a_{2}, a_{1}, a_{0} \\ with \ a_{n}\neq 0

In this exercise, we have two cases and both will be polynomial functions with degree 3 because we have three real roots in each case. So:

<h3>First.</h3>

The roots are:

x= -1, -1, 2

So we can write this polynomial functions as the product of linear factors:

f(x)=(x-(-1))(x-(-1))(x-2) \\ \\ f(x)=(x+1)^2(x-2)

Since we have to write it in standard form, let's expand:

f(x)=(x+1)^2(x-2) \\ \\ \\ By \ property: \\ \\ (a+b)^2=a^2+2ab+b^2 \\ \\ \\ f(x)=(x^2+2x+1)(x-2) \\ \\ f(x)=x^3+2x^2+x-2x^2-4x-2 \\ \\ \\ Combine \ like \ terms: \\ \\ x^3+(2x^2-2x^2)+(x-4x)-2 \\ \\ \\ \boxed{f(x)=x^3-3x-2}

<h3>Second.</h3>

The roots are:

x= -2, 0, 3

Writing the polynomial function as the product of linear factors:

g(x)=(x-(-2))(x-0)(x-3) \\ \\ g(x)=(x+2)x(x-3) \\ \\ g(x)=x(x+2)(x-3) \\ \\ \\ Distributive \property: \\ \\ g(x)=x(x^2-3x+2x-6) \\ \\ g(x)=x(x^2-x-6) \\ \\ \\ Distributive \ property \ again: \\ \\ \boxed{g(x)=x^3-x^2-6x}

<h2>Learn more:</h2>

Degree of polynomial functions: brainly.com/question/5451252

#LearnWithBrainly

7 0
3 years ago
Read 2 more answers
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