The answer is 3 because 3×5=15
85,000 milligrams is equal to 85 grams! :)
She plays soccer and golf for a total of 125 minutes:
s + g = 125
She plays soccer 45 minutes more than she plays golf:
s = g + 45 this is for A
B= 40 minutes of golf everyday
C= Yes, because in fact, she plays 85 minutes of soccer everyday, and 85 is greater than 80, so yes she CAN play 80 minutes of soccer every day. Perhaps they meant possible to spend ONLY 80 minutes, then NO, that wouldn't be possible, because then by playing 45 minutes more soccer than golf, she wouldn't have played enough to have 125 total minutes of total play. Technically the way the question is worded, the answer is yes.
I hope this helps!
Answer:

Step-by-step explanation:
Let the salary or A is x and salary of B is y.
now,
Condition one,The sum of 3/4th of A’s salary and 5/3rd of B’s salary is ₹16,000.
writing above statement in equation form,

Multiplying above equation with twelve,

and condition two,
The difference of their salaries is ₹2000

Multiplying above equation with 20

On adding equation 1 and equation 2,

Substituting the value of x in,


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