Answer:
<h2>
The eleventh term of the sequence is 64</h2>
Step-by-step explanation:
The sequence given is an arithmetic sequence
14, 19, 24, …………., 264
The nth term of an arithmetic sequence is given as;
Tn = a+(n-1)d where;
a is the first term = 14
d is the common difference = 19-14=24-19 = 5
n is the number of terms = 11(since we are to look for the eleventh term of the sequence)
substituting the given values in the formula given;
T11 = 14+(11-1)*5
T11 = 14+10(5)
T11 = 14+50
T11 = 64
The eleventh term of the sequence is 64
Answer:
170/8
Step-by-step explanation:
the steps are in the pic
Simplifying
x + 0.7 = 1 + -0.2x
Reorder the terms:
0.7 + x = 1 + -0.2x
Solving
0.7 + x = 1 + -0.2x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '0.2x' to each side of the equation.
0.7 + x + 0.2x = 1 + -0.2x + 0.2x
Combine like terms: x + 0.2x = 1.2x
0.7 + 1.2x = 1 + -0.2x + 0.2x
Combine like terms: -0.2x + 0.2x = 0.0
0.7 + 1.2x = 1 + 0.0
0.7 + 1.2x = 1
Add '-0.7' to each side of the equation.
0.7 + -0.7 + 1.2x = 1 + -0.7
Combine like terms: 0.7 + -0.7 = 0.0
0.0 + 1.2x = 1 + -0.7
1.2x = 1 + -0.7
Combine like terms: 1 + -0.7 = 0.3
1.2x = 0.3
Divide each side by '1.2'.
x = 0.25
Simplifying
x = 0.25
I only know 1 way.
1/10 because you will do it 10 times
The answer is 6.524. Hope this helps! :D
