Answer:
the 4th one, hop this helps sorry if I wasn't right.
Answer:
The probability that cards # 1, # 2, and # 3 are still in order on the top of the stack is 0.045%.
Step-by-step explanation:
Since a politician is about to give a campaign speech and is holding a stack of thirteen cue cards, of which the first 3 are the most important, and just before the speech, she drops all of the cards and picks them up in a random order, to determine what is the probability that cards # 1, # 2, and # 3 are still in order on the top of the stack, the following calculation must be performed:
1/13 x 1/13 x 1/13 = X
0.076 x 0.076 x 0.076 = X
0.00045 = X
0.00045 x 100 = 0.045
Therefore, the probability that cards # 1, # 2, and # 3 are still in order on the top of the stack is 0.045%.
Surfae area
we have 5 faces for the top shape
6 faces for the bottom
find areas of both
top=3*3+3*3+3*3+3*3=45
bottom one=3*10+3*3+3*3+3*10+3*10+3*(10-3)=129
add
45+129=174 mm^2
answer is B
volue
top shape is 3*3*3=27 mm^3
bottom is 10*3*3=90
add
27+90=117 mm^3
answer is C
6. 174 m^2 B
7. 117 mm^2 C
Answer:
Step-by-step explanation:
Equation 1) y = x² + 10x + 11
Equation 2) y = x² + x - 7
Subtract equations from one another.
9x = 18
Divide both sides by 9.
x = 2
Plug in 2 for x in the first equation.
y = x² + 10x + 11
y = 2² + 10(2) + 11
Simplify.
y = 4 + 20 + 11
y = 35
Plug in 35 for y and 2 for x in the first equation to check your work.
y = x² + 10x + 11
35 = 2² + 10(2) + 11
35 = 4 + 20 + 11
35 = 24 + 11
35 = 35
So, we know that our answer is correct! :))
x = 2, y = 35