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3 years ago

15

If $396 is invested at an interest rate of 13% per year and is compound continuously, how much will the investment be worth in 3

years?

1 answer:

Sveta_85 [38]3 years ago

7 0

Answer:

The investment at the end of the period will be $584.89.

Step-by-step explanation:

FV = PV e⁽ⁿˣ⁾

FV = Future Value = ?

PV = Present Value = $396

n = Interest Rate = 13%

x = time in years = 3

e = mathematical constant = 2.7183

FV = 396 x 2.7183⁽⁰°¹³ ˣ ³⁾

FV = 396 x 1.4770

FV = $584.89

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$\vec r_v\times\vec r_u=3\cos u\sin^2v\,\vec\imath+3\sin u\sin^2v\,\vec\jmath+3\sin v\cos v\,\vec k$

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$\displaystyle\iint_C\vec F\cdot\mathrm d\vec S=\int_0^{2\pi}\int_0^{\pi/2}((2\sqrt3\cos v+2)\,\vec k)\cdot(\vec r_v\times\vec r_u)\,\mathrm dv\,\mathrm du$

$\displaystyle=3\int_0^{2\pi}\int_0^{\pi/2}\sin2v(\sqrt3\cos v+1)\,\mathrm dv\,\mathrm du$

$=\boxed{2(3+2\sqrt3)\pi}$

b. Let $D$ be the disk that closes off the hemisphere $C$ , parameterized by

$\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath$

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$\vec s_v\times\vec s_u=-u\,\vec k$

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