Answer:
- large: 40 lbs
- small: 20 lbs
Step-by-step explanation:
A system of equations can be written for the weights of the boxes based on the relationships given in the problem statement. One equation will be for the total weight of 1 large and 1 small box; the other will be for the total weight of 70 large and 60 small boxes.
Let L and S represent the weights of Large and Small boxes, respectively. The system of equations is ...
L + S = 60 . . . . . . combined weight is 60 lbs
70L +60S = 4000 . . . . weight of boxes in the truck
__
We can solve this by substituting for s in the second equation.
70L +60(60 -L) = 4000
10L = 400 . . . . . . . . . subtract 3600, simplify
L = 40
S = 60 -L = 20
A large box weighs 40 pounds; a small box weighs 20 pounds.
Using derivatives, it is found that the best estimate of f '(2) based on this table of values is of 10.
The rate of change <u>from x = 0 to x = 2</u> is given by:

From <u>x = 2 to x = 4</u>, it is given by:

The average of these rates is:

Hence, the best estimate of f '(2) based on this table of values is of 10.
To learn more about derivatives, brainly.com/question/18590720
Answer:
R= diameter ÷ 2
Step-by-step explanation:
the radius is half the diameter.
The unit rat is the cost per 1 unit
cost per 1 tomatoe
3.4/4=1.7/2=0.85/1
unit rate is $0.85 per tomatoe
The general term for the arithmetic sequence; -13, -11, -9, -7 is Tn = -15 - 2n.
<h3>Arithmetic progression</h3>
-13, -11, -9, -7
- First term, a = -13
- Second term = -11
Common difference, d = Second term - first term
= -11 - (-13)
= -11 + 13
= 2
Therefore,
Tn = a + (n - 1)d
Where,
Tn = a + (n - 1)d
= -13 + (n - 1)2
= -13 - 2n - 2
Tn = -15 - 2n
So therefore, the general term for the arithmetic sequence; -13, -11, -9, -7 is Tn = -15 - 2n.
Learn more about arithmetic progression:
brainly.com/question/6561461
#SPJ1