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Pachacha [2.7K]
4 years ago
5

11-5 7/10 please help

Mathematics
2 answers:
Dima020 [189]4 years ago
6 0
SO 11-5 is going to give us 6 7/10=0.7
LenKa [72]4 years ago
5 0
I'm assuming it's

(11-5) • (7/10)

So use PEMDAS

First, start with parentheses in the order they appear

(11-5) = 1

(7/10) = .7

1 • .7 = 0.7
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Find the number whose arithmetic square root is 0.6
slavikrds [6]

Answer: 0.36

Step-by-step explanation:

6/10 x 6.10= 36/100

5 0
3 years ago
What is the distance between (-3,5) (7,5)
Firlakuza [10]

Answer:

10 units

Step-by-step explanation:

use distance formula:  d = square root of the difference of the y-values minus the difference of the x-values

d = \sqrt{(5-5)^2+(7--3)^2}

d = \sqrt{(0)^2+(10)^2}

d = \sqrt{100}

d = 10 units

4 0
3 years ago
Read 2 more answers
1. One week Carlos bought 3 bags of Tabitha Tidbits and 4 bags of Figaro Flakes for $43.00. The next week he bought 3 bags of Ta
d1i1m1o1n [39]
Tabitha Tidbits costs $7 per bag, and Figaro Flakes is $5.50 per bag.
You need to set up a system of equations. Use "x" for Tabitha Tidbits and "y" for Figaro Flakes, and let the total cost of each trip equal c. Using the equation ax+by=c, substitute the cost of each trip in for c, and the number of bags for each food for a and b respectively. The two equations will be:
3x+4y=43
3x+6y=54
Isolate x in the first equation and you will get:
x=(43-4y)/3
Substitute the above equation for x into the other equation:
3*((43-4y)/3)+6y=54
Isolate y in this equation, and you will get 11/2, which is 5.5
So the cost of one bag of Figaro Flakes is $5.50
Now substitute this into the equation where you isolated x:
(43-4(5.5))/3
You will get x=7, so a bag of Tabitha Tidbits is $7
3 0
3 years ago
uppose germination periods, in days, for grass seed are normally distributed and have a known population standard deviation of 2
natka813 [3]

Answer: 0.701

Step-by-step explanation:

Formula :  EBM =z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}} , where \alpha= significance level , \sigma = Population standard deviation, n= sample size.

As per given,  n= 22

\sigma = 2

Critical z- value for 90% confidence level : z_{\alpha/2}=1.645

Then,

 EBM =(1.645)\dfrac{2}{\sqrt{22}}\\\\=(1.645)\dfrac{2}{4.690416}\\\\\approx0.701

Hence ,  error bound (EBM) of the confidence interval with a 90% confidence level= ± 0.701

5 0
3 years ago
I'm horrible at probability problems someone help :(
icang [17]
I can’t see it there’s no picture lol
8 0
3 years ago
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