To find the intersection points, you take x^2 - 4x + 9 = -2x + 17
This gives x^2 - 2x - 8 = 0,
which factorises to (x - 4)(x + 2) = 0, giving the solutions x = 4 or x = -2
From the graph, we can see that x is positive, meaning x = 4, so a = 4.
Substituting x = 4 into y = -2x + 17, we get y = -2(4) + 17 = 9, so b = 9.
a + b = 4 + 9 = 13. The answer is B.
Answer:
<h2>|DB| = 6</h2>
Step-by-step explanation:
If ABCD is a rhombus then the diagonals AC and BD are perpendicular and intersect in half.
Let E be the point of intersection of the diagonals.
Therefore:
AE ≅ EC and DE ≅ EB ⇒ |AE| = |EC| and |DE| = |EB|.
DB = DE + EB
|EB| = 3 ⇒ |DB| = 3 + 3 = 6
ABCD it's not a rectangle because in each rectangle diagonals are congruent and intersect in half.
okay but like do you even need any help??
<span>x/x+6 simplfiy to 1/6 = 0, So your answer is 0</span>
