Answer: (A) The image of JKL after a 90° counterclockwise about the origin is shown in figure 1. (B) The image of JKL after a reflection across the y-axis is shown in figure 2.

Explanation:

(A)

From the given figure it is noticed that the coordinate points are J(-4,1), K(-4,-2) and L(-3,-1).

If a shape rotate 90 degree counterclockwise about the origin, then,

$(x,y)\rightarrow (-y,x)$

$J(-4,1)\rightarrow J'(-1,-4)$

$K(-4,-2)\rightarrow K'(2,-4)$

$L(-3,-1)\rightarrow L'(1,-3)$

Therefore, the vertex of imare are J'(-1,-4), K'(2,-4) and L'(1,-3). The graph is shown in figure (1).

(B)

If a figure reflect across the y-axis then,

$(x,y)\rightarrow (-x,y)$

$J(-4,1)\rightarrow J''(4,1)$

$K(-4,-2)\rightarrow K''(2,-4)$

$L(-3,-1)\rightarrow L''(3,-1)$

Therefore, the vertex of imare are J''(4,1), K''(2,-4) and L''(3,-1). The graph is shown in figure (2).

8 0

3 years ago

Which is the best description for the lines i and k?

Sonbull [250]

Answer: intersecting but not perpendicular

Step-by-step explanation: Let's start by eliminating a few options.

First off, parallel lines are coplanar lines that do not intersect.

In the diagram shown, lines i and k do intersect

so option A doesn't make any sense.

We can also eliminate option C because by definition,

parallel lines do not intersect  so we can cross this off.

We also can't conclude that lines i and k are perpendicular,

because we don't have a box at the vertex and from the

diagram shown, it doesn't look like they form a perfect right angle.

That leaves us with option D.

Notice that these two lines cross at a point.

When two lines cross at a point, we say that they intersect.

So they are intersecting lines but not perpendicular.

6 0

2 years ago