All categories

3 years ago

Write the curve described by the parametric equations x=5-cost and y=2+2sint in rectangular form.

Mathematics

1 answer:

Vedmedyk [2.9K]3 years ago

8 0

Answer:

Step-by-step explanation:

Its right I'm sure of it!

You might be interested in

What is the solution for -10 < x - 9?

enyata [817]

-10 < x - 9

-10+9 < x - 9+9

-1<x, or
x> - 1

4 0

3 years ago

An 18 foot ladder is leaned against a wall if the base of the ladder is 8 feet from the wall how high up on the wall will the la

Aloiza [94]

Answer:

16.12ft

Step-by-step explanation:

Check attachment

4 0

3 years ago

Consider the inverse function. Which conclusions can be drawn about f(x) = x2 + 2? Select three options. f(x) has a limited rang

PolarNik [594]

Answer:

f(x) has a limited range

f(x) has a maximum at the point (0, 2)

f(x) has a y-intercept at the point (0, 2).

Step-by-step explanation:

Given the function;

f(x) = x^2+2

The domain is the value of the input variables for which the function will exist. According to the expression given, the function exists on all real values of x. The same goes with range which deals with the output values. It also exists on all real values from 2 and above.

Hence f(x) have a limited range (since values less than 2 are not included compare to domain that exists on all real values) and does not have a restricted domain.

For the x intercept, x intercept occur at y = 0

substitute y = 0 into the function and get y

if y = f(x)

y = x^2+2

0 = x^2 + 2

x^2 = -2

x = 2i

Hence f(x) does not have an x-intercept of (2, 0)

For the y intercept, y intercept occur at x = 0

substitute x = 0 into the function and get y

if y = f(x)

y = x^2+2

y = 0^2 + 2

y = 2

Hence f(x) has a y-intercept at point (0, 2)

f(x) is at maximum if d(fx))/dx = 0

d(fx))/dx = 2x

since d(fx))/dx = 0

0 = 2x

x = 0

substitute x = 0 into the function

f(x) = x^2 + 2

y = 0^2+2

y = 2

Hence f(x) has a maximum at the point (0, 2)

5 0

2 years ago

Read 2 more answers

What is the general process for solving an equation with one variable?

elena55 [62]

Greetings!

"What is the general process for solving an equation with one variable?"...

Typically when solving an equation with one variable, your objective is to isolate the variable on one side of the equation. This can be done adding/subtracting number to cancel them out on one side. You can also multiply/divide coefficients in order to isolate a variable.

Example:
 $2x+4=64$
Add -4 to both sides to isolate the variable.
 $(2x+4)+(-4)=(64)+(-4)$ 
Simplify.
 $2x=60$
Divide both sides by 2 to isolate the variable on one side.
$(2x)/2=(60)/2$
$x=30$

Hope this helps.
-Benjamin

5 0

3 years ago

Given the table below, determine if the data represents a linear or an exponential function and find a possible formula for the

strojnjashka [21]

The answer is C) y=14(0.9)ˣ and it's an exponential function

PROOF

Give to x the respective values of x & calculate y, using y = 14(0.9)ˣ

x | y
---------|---------
0 | 14(0.9)⁰ = 14
1 | 14(0.9)¹ = 12.6
2 | 14(0.9)² = 11.34
3 | 14(0.9)³ = 10.206
4 | 14(09)⁴ = 9.1845

4 0

3 years ago