Answer:
the answer is 4
Step-by-step explanation:
I did the homework
In order from least to greatest:
5/10 , 7/12 , 4/6
You have to find a common denominator of all 3 numbers which is 60 and then you proceed with the next steps.
Answer:
Step-by-step explanation:
Using first equation in the second gives you
x-3(-2x+1)=11
x+6x-3=11
7x-3=11
7x=14
x=2, making y=-2x+1 become
y=-2(2)+1
y=-4+1
y=-3 so the solution is the point
(2,-3)
An aritmetic sequence is like this

where a1=first term and d=common difference
geometric is

where a1=first term and r=common ratio
can it be both aritmetic and geometric
hmm, that means that the starting terms should be the same
therfor we need to solve

what values of d and r make all natural numbers of n true?
are there values that make all natural numbers for n true?
when n=1, then d(1-1)=0 and r^(1-1)=1, so already they are not equal
the answer is no, a sequence cannot be both aritmetic and geometric