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3 years ago

35. Graph the following system of equations and find the x-coordinate of the solution.

Mathematics

1 answer:

Ronch [10]3 years ago

4 0

9514 1404 393

Answer:

(b) x = -2

Step-by-step explanation:

The graph shows the lines intersect at (x, y) = (-2, 3).

The x-coordinate of the solution is x = -2.

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Given: ∠T ≅ ∠V; ST || UV

Novay_Z [31]

The respective missing proofs are; Alternate interior; Transitive property; Converse alternate interior angles theore

<h3>How to complete two column proof?</h3>

We are given that;

∠T ≅ ∠V and ST || UV

From images seen online, the first missing proof is Alternate Interior angles because they are formed when a transversal intersects two coplanar lines.

The second missing proof is Transitive property because angles are congruent to the same angle.

The last missing proof is Converse alternate interior angles theorem

because two lines are intersected by a transversal forming congruent alternate interior angles, then the lines are parallel.

Read more about Two Column Proof at; brainly.com/question/1788884

#SPJ1

7 0

2 years ago

A random sample of soil specimens was obtained, and the amount of organic matter (%) in the soil was determined for each specime

MrRissso [65]

Answer:

We conclude that the true average percentage of organic matter in such soil is something other than 3% at 10% significance level.

We conclude that the true average percentage of organic matter in such soil is 3% at 5% significance level.

Step-by-step explanation:

We are given a random sample of soil specimens was obtained, and the amount of organic matter (%) in the soil was determined for each specimen;

1.10, 5.09, 0.97, 1.59, 4.60, 0.32, 0.55, 1.45, 0.14, 4.47, 1.20, 3.50, 5.02, 4.67, 5.22, 2.69, 3.98, 3.17, 3.03, 2.21, 0.69, 4.47, 3.31, 1.17, 0.76, 1.17, 1.57, 2.62, 1.66, 2.05.

Let $\mu$ = true average percentage of organic matter

So, Null Hypothesis, $H_0$ : $\mu$ = 3% {means that the true average percentage of organic matter in such soil is 3%}

Alternate Hypothesis, $H_A$ : $\mu \neq$ 3% {means that the true average percentage of organic matter in such soil is something other than 3%}

The test statistics that will be used here is One-sample t-test statistics because we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean percentage of organic matter = 2.481%

s = sample standard deviation = 1.616%

n = sample of soil specimens = 30

So, the test statistics = $\frac{2.481-3}{\frac{1.616}{\sqrt{30} } }$ ~ $t_2_9$

= -1.76

The value of t-test statistics is -1.76.

(a) Now, at 10% level of significance the t table gives a critical value of -1.699 and 1.699 at 29 degrees of freedom for the two-tailed test.

Since the value of our test statistics doesn't lie within the range of critical values of t, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the true average percentage of organic matter in such soil is something other than 3% at 10% significance level.

(b) Now, at 5% level of significance the t table gives a critical value of -2.045 and 2.045 at 29 degrees of freedom for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the true average percentage of organic matter in such soil is 3% at 5% significance level.

8 0

3 years ago

Bill drove 715 miles in 11 hours.

Verizon [17]

Answer: It would take 7 hours.

Step-by-step explanation:

715/11 = 65

65 miles per hour

455/65 = 7

6 0

2 years ago