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belka [17]
3 years ago
7

PLS HELP!!!: A meter is about the distance from one hand to the other when your arms are stretched out if 5 friends stood with t

heir arms stretched and fingers touching about how many meters would that be in length??
Mathematics
2 answers:
steposvetlana [31]3 years ago
5 0

Answer:5 meters

Step-by-step explanation:

1 meter=1 person stretched out

5meters=5 people stretched out

Zanzabum3 years ago
4 0

Answer:

5 meters???

Step-by-step explanation:

each friend has arms

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I think the answer (-2, 6)

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yawa3891 [41]

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233.5

Step-by-step explanation

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Alla [95]

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5 0
2 years ago
A solution initially contains 200 bacteria. 1. Assuming the number y increases at a rate proportional to the number present, wri
GuDViN [60]

Answer:

1.\frac{dy}{dt}=ky

2.543.6

Step-by-step explanation:

We are given that

y(0)=200

Let y be the number of bacteria at any time

\frac{dy}{dt}=Number of bacteria per unit time

\frac{dy}{dt}\proportional y

\frac{dy}{dt}=ky

Where k=Proportionality constant

2.\frac{dy}{y}=kdt,y'(0)=100

Integrating on both sides then, we get

lny=kt+C

We have y(0)=200

Substitute the values then , we get

ln 200=k(0)+C

C=ln 200

Substitute the value of C then we get

ln y=kt+ln 200

ln y-ln200=kt

ln\frac{y}{200}=kt

\frac{y}{200}=e^{kt}

y=200e^{kt}

Differentiate w.r.t

y'=200ke^{kt}

Substitute the given condition then, we get

100=200ke^{0}=200 \;because \;e^0=1

k=\frac{100}{200}=\frac{1}{2}

y=200e^{\frac{t}{2}}

Substitute t=2

Then, we get y=200e^{\frac{2}{2}}=200e

y=200(2.718)=543.6=543.6

e=2.718

Hence, the number of bacteria after 2 hours=543.6

4 0
3 years ago
Matthew wants his run today to take no more than 90 minutes. He already has run 30 minutes at a pace of 10 minutes per mile.
denis23 [38]

Answer: 10x-30=90 I think 10x=90-30, 10x=60, x=60/10, x=6

Step-by-step explanation:

5 0
3 years ago
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