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alexira [117]
3 years ago
7

The box is 2.1 feet long,2.7 feet wide and 3.2 feet high. What is closest to the total surface area of the box?

Mathematics
2 answers:
galina1969 [7]3 years ago
3 0
So the actually surface area can be split up by dif parts....meaning
2 side is 2.7*3.2*2 = 17.28
2 side is 3.2*2.1*2 = 13.44
2 sides is 2.1*2.7*2=  11.34

then u add up the areas = 42.06ft^2

then u look for what is the clossest...and that is 42gt^2
shtirl [24]3 years ago
3 0
17.28 for one side...
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Use integration by parts to find the integrals in Exercise.<br> ∫(x+6)ex dx.
skelet666 [1.2K]

Answer:

xe^x+5e^x

Step-by-step explanation:

We have given integral \int (x+6)e^xdx

\int (xe^x+6e^x)dx

\int (I_1+I_2)dx , here I_1=xe^x and I_2=6e^x

Now first integrate I_1

So I_1=\int xe^x

Integrating by part

I_1=x\int e^x-\int e^x\frac{d}{dx}x

I_1=x e^x- e^x

I_2=6\int e^x=6e^x

So I=I_1+I_2=xe^x-e^x+6e^x=xe^x+5e^x

5 0
3 years ago
3(n+4)=21 what does n =?
Brilliant_brown [7]

Answer:

3.

Step-by-step explanation:

3(n + 4) = 21

3n + 12 = 21

3n = 21 - 12 = 9

n = 3.

7 0
3 years ago
Read 2 more answers
How do i find the volume of these similar solids? round to the nearest tenth HELP
FromTheMoon [43]

Answer:

The volume of the larger solid is 592.6\ mm^3

Step-by-step explanation:

<u><em>The question is</em></u>

If these solids are similar, find the volume of the larger solid

step 1      

Find the scale factor

we know that

If two solids are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor

Let

x ----> the height of the larger solid in mm

y ----> the height of the smaller solid in mm

z ---> the scale factor

z=\frac{x}{y}

we have

x=4\ mm\\y=3\ mm

substitute

z=\frac{4}{3} ---> scale factor

step 2

Find the volume of the larger solid

we know that

If two solids are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

Let

x ----> the volume of the larger solid in cubic millimeters

y ----> the volume of the smaller solid in in cubic millimeters

z ---> the scale factor

z^3=\frac{x}{y}

we have

z=\frac{4}{3}

y=250\ mm^3

substitute the values

(\frac{4}{3})^3=\frac{x}{250}

solve for x

(\frac{64}{27})=\frac{x}{250}

x=250(\frac{64}{27})

x=592.6\ mm^3

4 0
3 years ago
Please help me out :P
Veseljchak [2.6K]

cos θ = \frac{-4\sqrt{65} }{65}, sin θ = \frac{-7\sqrt{65} }{65}, cot  θ  = 4/7, sec  θ = \frac{-\sqrt{65} }{4}, cosec  θ  = \frac{-\sqrt{65} }{7}

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = \sqrt{7^{2} + 4^{2} } = \sqrt{49+16} = \sqrt{65}

sin θ = opposite/ hyp = \frac{7}{\sqrt{65} }

Rationalize, \frac{7}{\sqrt{65} } x \frac{\sqrt{65} }{\sqrt{65} } = \frac{7\sqrt{65} }{65}

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - \frac{7\sqrt{65} }{65}

cos   θ  = adj/hyp = \frac{4}{\sqrt{65} }

By rationalizing and knowing that cos  θ  is negative, cos θ  = -\frac{-4\sqrt{65} }{65}

cot θ  = 1/tan θ  = 1/7/4 = 4/7

sec θ  = 1/cos θ  = 1/\frac{4}{\sqrt{65} } = -\frac{-\sqrt{65} }{4}

cosec θ  = 1/sin θ  = 1/\frac{\sqrt{65} }{7} = \frac{-\sqrt{65} }{7}

Learn more about trigonometric ratios: brainly.com/question/24349828

#SPJ1

5 0
1 year ago
What is the correct factorization of x^6-y^6
Soloha48 [4]
(x^3 - y^3)(x^3 + y^3)

You can get this by factoring based on the a^2 - b^2 model 
3 0
3 years ago
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