18 t - 18 t * 30% = 18 t - 17 * 0,3 = 18 t - 5,4 t = 12,6 t
Answer:
X Intercept: (-10,0), Y Intercept: (0,2)
Step-by-step explanation:
Well, firstly you need to rewrite the equation to make it easier. After rewriting it you have the equation y=x/5+2 by adding the x to the right side and dividing everything by 5. Now simply plug in your zeroes in their respective places. For the x intercept, your y value must equal 0 so we have the equation 0=x/5+2. After solving it, x must be -10 in order for our y value to be 0 getting us for the x intercept (-10,0). For the y intercept, your x value must equal zero so you simply subsitute zero in the equation for x which I will do here: y=0/5+2. If our x value is zero, consequently, our y value will be 2 getting us for the y intercept, (0,2).
Answer:
LIMIT
The policy will pay for up to
$100,000 of damage to
another person's property.
The policy will pay only
$100 per incident for a
tow truck
DEDUCTIBLE
The policyholder must pay
the first $1,000 of repair
expenses before insurance
will pay for anything,
PREMIUM
The policy offers coverage
for a cost of $178 per month
The policyholder must
pay $500 semiannually
to the insurance provider
Step-by-step explanation:
LIMIT is the maximum amount an insurer will pay toward a covered claim
DEDUCTIBLE is the amount paid out of pocket toward a covered claim
PREMIUM is the amount paid regularly to keep the policy in force.
Answer:
The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
Of the 2809 people who responded to survey, 1634 stated that they currently use social media.
This means that 
98% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).
