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3 years ago

5

-6x -8y = 28 6х + 4y =-28 would this be infinite many solutions or no solutions?

1 answer:

blondinia [14]3 years ago

5 0

-6x -8y = 28
6х + 4y =-28

would this be infinite many solutions or no solutions?

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an assembly line worker at Rob's Bicycle factory adds a seat to a bicycle at the rate of 2 seats in 11 minutes. Write a proporti

LuckyWell [14K]

Rate = 2 seats/11 minutes = 2/11 seats/min

Therefore the time required for s seats is
$(m \, min) = \frac{s \, seats}{ \frac{2}{11} \, \frac{seats}{min} } = \frac{11s}{2} \, min$
That is,
m = (11s)/2 min

When s = 16, obtain
$m = \frac{11(16)}{2} = 88 \, min$

When s = 19, obtain
$m = \frac{11(19)}{2} = 104.5 \, min$

Answers:
$m = \frac{11s}{2}$
When s = 16, m = 88 min
When s = 19, m = 104.5 min

3 0

3 years ago

What is the answer For -6k Plus 7K

Furkat [3]

-6k+7k equals 1k.................................

8 0

3 years ago

If John ran a 5-kilometer marathon, how long was that in meters? A. 500 m B. 1000 m C. 5,000 m D. 50,000 m

Karolina [17]

The answer is c- 5,000

7 0

3 years ago

Read 2 more answers

Please help me. I suck at math

serg [7]

Answer:

Answer is ...Obtuse

Step-by-step explanation:

$\frac{m$

$\frac{5x + 4}{2} = \frac{3}{2} x + 21$

$\frac{5x + 4}{2} = \frac{3x + 42}{2}$

$5x + 4 = 3x + 42$

$5x - 3x = 42 - 4$

$2x = 38$

$x = 19$

$substituting \: x = 19 \: \:in \: \: \: \: \: \: \: \\ m$

We get,

m<ABC =

$(5 \times 19) + 4 = 99$

Hence <ABC is obtuse

4 0

3 years ago

A spring has natural length 24 cm. Compare the work W1 done in stretching the spring from 24 cm to 34 cm with the work W2 done i

Scilla [17]

Answer:

From the analysis W1=W2.

they are directly related

Step-by-step explanation:

the work-done in stretching a spring can be expressed as

$W=\frac{1}{2}kx^2$

where k= spring constant

x= change on length of spring

Hence for W1

Given data

x= 34-24= 10 cm

solving in terms of k we have

$W=\frac{1}{2}k*10^2\\\W=\frac{1}{2}k*100\\\W=50k$

Hence for W2

Given data

x= 44-34= 10 cm

solving in terms of k we have

$W=\frac{1}{2}k*10^2\\\ W=\frac{1}{2}k*100\\\ W=50k$

4 0

3 years ago