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maks197457 [2]
3 years ago
14

What is 3 2/5 minus 1 9/10

Mathematics
2 answers:
cestrela7 [59]3 years ago
5 0
3\frac{2}{5}=3\frac{2\cdot2}{5\cdot2}=3\frac{4}{10}=3.4\\\\1\frac{9}{10}=1.9\\\\3\frac{2}{5}-1\frac{9}{10}=3.4-1.9=\boxed{1.5}
ivanzaharov [21]3 years ago
3 0
The answer is 1 1/2 or 1 5/10

Here is my work if you don't understand, ASK!!

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Answer:

<h3>A≈50.27in²</h3>

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Write three equivalent ratios for the given ratio.<br>7. 12​
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Step-by-step explanation:

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You drove 360 miles in 6 hours. How many miles did you drive per per hour?​
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If a,b,c and d are positive real numbers such that logab=8/9, logbc=-3/4, logcd=2, find the value of logd(abc)
Eva8 [605]

We can expand the logarithm of a product as a sum of logarithms:

\log_dabc=\log_da+\log_db+\log_dc

Then using the change of base formula, we can derive the relationship

\log_xy=\dfrac{\ln y}{\ln x}=\dfrac1{\frac{\ln x}{\ln y}}=\dfrac1{\log_yx}

This immediately tells us that

\log_dc=\dfrac1{\log_cd}=\dfrac12

Notice that none of a,b,c,d can be equal to 1. This is because

\log_1x=y\implies1^{\log_1x}=1^y\implies x=1

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\log_db=\dfrac{\ln b}{\ln d}=\dfrac{\frac{\ln b}{\ln c}}{\frac{\ln d}{\ln c}}=\dfrac{\log_cb}{\log_cd}=\dfrac1{\log_bc\log_cd}

so that

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Similarly,

\log_da=\dfrac{\ln a}{\ln d}=\dfrac{\frac{\ln a}{\ln b}}{\frac{\ln d}{\ln b}}=\dfrac{\log_ba}{\log_bd}=\dfrac{\log_db}{\log_ab}

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So we end up with

\log_dabc=-\dfrac34-\dfrac23+\dfrac12=-\dfrac{11}{12}

###

Another way to do this:

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\log_cd=2\implies c^2=d\implies\log_dc^2=1\implies\log_dc=\dfrac12

Then

abc=(c^{-4/3})^{9/8}c^{-4/3}c=c^{-11/6}

So we have

\log_dabc=\log_dc^{-11/6}=-\dfrac{11}6\log_dc=-\dfrac{11}6\cdot\dfrac12=-\dfrac{11}{12}

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