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Liula [17]
3 years ago
5

Complete the passage to describe velocity vs time graphs.A velocity vs time graph is a graph that shows the relationship between

the velocity of an object over time. ________________ is plotted on the x-axis in seconds, and the _________________ of the object is plotted on the y-axis in meters per second.
Mathematics
1 answer:
Fiesta28 [93]3 years ago
4 0
1)Time is plotted on the x-axis in seconds
2)Velocity of the object is plotted on the y-axis in meters per second
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If w÷3=3(w-1)-1 find the value of w<br><br>​
Licemer1 [7]

Answer:

3/2

Step-by-step explanation:

w/3=3(w-1)-1

w=9w-9-3

-8w=-12

w=3/2

5 0
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Explain how you use estimation to check the reasonableness of a solution to a practical problem.
Oxana [17]

Answer:

Well, one way to use reasonableness is to estimate the answer to see if your answer is an outrageous answer or not. So, looking at your problem, you see that you are multiplying a two hundred something number by 4 and then subtracting 10 from it.

Step-by-step explanation:

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A nursery sells English, tea, and miniature rosebushes in red, pink, yellow, and white. How many
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is this year 3 math? Its 4

8 0
3 years ago
HELP WILL MARK BRAINLIEST!! NO FAKE ANSWERSS
lord [1]

Answer:

1) not polynomial

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hope it helps you

4 0
2 years ago
Please help me with this​
denis23 [38]

Answer:

20) \displaystyle [4, 1]

19) \displaystyle [-5, 1]

18) \displaystyle [3, 2]

17) \displaystyle [-2, 1]

16) \displaystyle [7, 6]

15) \displaystyle [-3, 2]

14) \displaystyle [-3, -2]

13) \displaystyle NO\:SOLUTION

12) \displaystyle [-4, -1]

11) \displaystyle [7, -2]

Step-by-step explanation:

20) {−2x - y = −9

{5x - 2y = 18

⅖[5x - 2y = 18]

{−2x - y = −9

{2x - ⅘y = 7⅕ >> New Equation

__________

\displaystyle \frac{-1\frac{4}{5}y}{-1\frac{4}{5}} = \frac{-1\frac{4}{5}}{-1\frac{4}{5}}

\displaystyle y = 1[Plug this back into both equations above to get the x-coordinate of 4]; \displaystyle 4 = x

_______________________________________________

19) {−5x - 8y = 17

{2x - 7y = −17

−⅞[−5x - 8y = 17]

{4⅜x + 7y = −14⅞ >> New Equation

{2x - 7y = −17

_____________

\displaystyle \frac{6\frac{3}{8}x}{6\frac{3}{8}} = \frac{-31\frac{7}{8}}{6\frac{3}{8}}

\displaystyle x = -5[Plug this back into both equations above to get the y-coordinate of 1]; \displaystyle 1 = y

_______________________________________________

18) {−2x + 6y = 6

{−7x + 8y = −5

−¾[−7x + 8y = −5]

{−2x + 6y = 6

{5¼x - 6y = 3¾ >> New Equation

____________

\displaystyle \frac{3\frac{1}{4}x}{3\frac{1}{4}} = \frac{9\frac{3}{4}}{3\frac{1}{4}}

\displaystyle x = 3[Plug this back into both equations above to get the y-coordinate of 2]; \displaystyle 2 = y

_______________________________________________

17) {−3x - 4y = 2

{3x + 3y = −3

__________

\displaystyle \frac{-y}{-1} = \frac{-1}{-1}

\displaystyle y = 1[Plug this back into both equations above to get the x-coordinate of −2]; \displaystyle -2 = x

_______________________________________________

16) {2x + y = 20

{6x - 5y = 12

−⅓[6x - 5y = 12]

{2x + y = 20

{−2x + 1⅔y = −4 >> New Equation

____________

\displaystyle \frac{2\frac{2}{3}y}{2\frac{2}{3}} = \frac{16}{2\frac{2}{3}}

\displaystyle y = 6[Plug this back into both equations above to get the x-coordinate of 7]; \displaystyle 7 = x

_______________________________________________

15) {6x + 6y = −6

{5x + y = −13

−⅚[6x + 6y = −6]

{−5x - 5y = 5 >> New Equation

{5x + y = −13

_________

\displaystyle \frac{-4y}{-4} = \frac{-8}{-4}

\displaystyle y = 2[Plug this back into both equations above to get the x-coordinate of −3]; \displaystyle -3 = x

_______________________________________________

14) {−3x + 3y = 3

{−5x + y = 13

−⅓[−3x + 3y = 3]

{x - y = −1 >> New Equation

{−5x + y = 13

_________

\displaystyle \frac{-4x}{-4} = \frac{12}{-4}

\displaystyle x = -3[Plug this back into both equations above to get the y-coordinate of −2]; \displaystyle -2 = y

_______________________________________________

13) {−3x + 3y = 4

{−x + y = 3

−⅓[−3x + 3y = 4]

{x - y = −1⅓ >> New Equation

{−x + y = 3

________

\displaystyle 1\frac{2}{3} ≠ 0; NO\:SOLUTION

_______________________________________________

12) {−3x - 8y = 20

{−5x + y = 19

⅛[−3x - 8y = 20]

{−⅜x - y = 2½ >> New Equation

{−5x + y = 19

__________

\displaystyle \frac{-5\frac{3}{8}x}{-5\frac{3}{8}} = \frac{21\frac{1}{2}}{-5\frac{3}{8}}

\displaystyle x = -4[Plug this back into both equations above to get the y-coordinate of −1]; \displaystyle -1 = y

_______________________________________________

11) {x + 3y = 1

{−3x - 3y = −15

___________

\displaystyle \frac{-2x}{-2} = \frac{-14}{-2}

\displaystyle x = 7[Plug this back into both equations above to get the y-coordinate of −2]; \displaystyle -2 = y

I am delighted to assist you anytime my friend!

7 0
3 years ago
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