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MatroZZZ [7]
3 years ago
14

The cost of one pound of bananas is greater than $0.41 and less than $0.50. Sarah pays $3.40 for x pounds of bananas. Which ineq

uality represents the range of possible pounds purchased? 0.41 < 0.41 less than StartFraction 3.40 over x EndFraction less than 0.50. < 0.50 0.41 < 0.41 less than StartFraction x over 3.40 EndFraction less than 0.50. < 0.50 0.41 < 3.40x < 0.50 0.41 < 3.40 + x < 0.50
Mathematics
2 answers:
Elanso [62]3 years ago
6 0

Answer:

0.41 x < 3.40 < 0.50 x

Step-by-step explanation:

trust bro

pls make me brainliest

DochEvi [55]3 years ago
5 0

Answer:

0.41 x < 3.40 < 0.50 x

If there is a whole number of pounds it could be: x = 8 pounds

0.41 * 8 = 3.28,  0.50 * 8 = 4

3.28 < 3.40 < 4

Answer:

Inequality is

0.41 x < 3.40 < 0.50 x

Step-by-step explanation:

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I am a number greater than $4,000 less than $6,000 by ones digit and 10 digit are the same my 10,000
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Step-by-step explanation:

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2 years ago
Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2.4 h, and Car B traveled the dis
Arte-miy333 [17]
One way to go about this is to first list everything we know in the form of variables. This will make it easier to see how these numbers correlate instead of trying to remember formulas to plug these numbers into.

TimeA = 2.4h (time of Car A to travel)
TimeB = 4h (time of Car B to travel)
SpeedA = SpeedB + 22mph (Speed of Car A<span>)
</span>SpeedB = SpeedA - 22mph (Speed of Car B<span>)
</span>Distance = x (the distance traveled by each car)

We are looking for SpeedA. How can we find this? Well, we know that speed multiplied by time is equal to distance, so let's start there.

SpeedA * 2.4h = x
<span>(SpeedB + 22mph) * 2.4h = x
</span>(2.4h * SpeedB) + 52.8miles = x

We also know that:
SpeedB * 4h = x

Since both of these equations are equal to x, we can combine them:
SpeedB * 4h = x = <span>(2.4h * SpeedB) + 52.8miles
</span>SpeedB * 4h = <span>(2.4h * SpeedB) + 52.8miles
</span>1.6h * Speed B = 52.8miles
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</span>
Therefore, Car A was traveling at 55mph.
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4 years ago
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Anika [276]
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3 years ago
Solve the system of linear equations in two variables by elimination or substitution.
taurus [48]

Answer:

( \frac{1}{2}, 0 )

Step-by-step explanation:

Given the 2 equations

4x + 3y = 2 → (1)

2x - 3y = 1 → (2)

Adding (1) and (2) term by term will eliminate the y- term, that is

6x = 3 ( divide both sides by 6 )

x = \frac{3}{6} = \frac{1}{2}

Substitute x = \frac{1}{2} into either of the 2 equations and evaluate for y

Substituting into (1)

4(\frac{1}{2} ) + 3y = 2

2 + 3y = 2 ( subtract 2 from both sides )

3y = 0 ⇒ y = 0

Solution is ( \frac{1}{2}, 0 )

8 0
3 years ago
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