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MatroZZZ [7]
2 years ago
14

The cost of one pound of bananas is greater than $0.41 and less than $0.50. Sarah pays $3.40 for x pounds of bananas. Which ineq

uality represents the range of possible pounds purchased? 0.41 < 0.41 less than StartFraction 3.40 over x EndFraction less than 0.50. < 0.50 0.41 < 0.41 less than StartFraction x over 3.40 EndFraction less than 0.50. < 0.50 0.41 < 3.40x < 0.50 0.41 < 3.40 + x < 0.50
Mathematics
2 answers:
Elanso [62]2 years ago
6 0

Answer:

0.41 x < 3.40 < 0.50 x

Step-by-step explanation:

trust bro

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DochEvi [55]2 years ago
5 0

Answer:

0.41 x < 3.40 < 0.50 x

If there is a whole number of pounds it could be: x = 8 pounds

0.41 * 8 = 3.28,  0.50 * 8 = 4

3.28 < 3.40 < 4

Answer:

Inequality is

0.41 x < 3.40 < 0.50 x

Step-by-step explanation:

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(x + 13y) + 8y=<br> :\ This is so confusing
anygoal [31]

Answer:

x+21 y

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Out of 100 employees at a company, 92 employees either work part time or work 5 days each week. There are 14 employees who work
Alexus [3.1K]

Answer: 0.02

Step-by-step explanation:

OpenStudy (judygreeneyes):

Hi - If you are working on this kind of problem, you probably know the formula for the probability of a union of two events. Let's call working part time Event A, and let's call working 5 days a week Event B. Let's look at the information we are given. We are told that 14 people work part time, so that is P(A) = 14/100 - 0.14 . We are told that 80 employees work 5 days a week, so P(B) = 80/100 = .80 . We are given the union (there are 92 employees who work either one or the other), which is the union, P(A U B) = 92/100 = .92 .. The question is asking for the probability of someone working both part time and fll time, which is the intersection of events A and B, or P(A and B). If you recall the formula for the probability of the union, it is

P(A U B) = P(A) +P(B) - P(A and B).

The problem has given us each of these pieces except the intersection, so we can solve for it,

If you plug in P(A U B) = 0.92 and P(A) = 0.14, and P(B) = 0.80, you can solve for P(A and B), which will give you the answer.

I hope this helps you.

Credit: https://questioncove.com/updates/5734d282e4b06d54e1496ac8

7 0
2 years ago
which of the following are right triangles: a triangle with side lenghts 6 inches, 8 inches,10 inches, a triangle with side leng
amid [387]

9514 1404 393

Answer:

  • (6, 8, 10) right
  • (8, 15, 17) right
  • (5, 12, 13) right

Step-by-step explanation:

It can be helpful to memorize a few of the Pythagorean triples that show up in Algebra problems. Their multiples also form right triangles.

  (3, 4, 5), (5, 12, 13), (7, 24, 25), (8, 15, 17), (9, 40, 41)

The triple (6, 8, 10) is the first one of these, multiplied by 2 inches.

The only triple that is a sequence of consecutive integers is (3, 4, 5), so you know immediately that (4, 5, 6) does not form a right triangle.

Of course, you can check any of them to see if the squares of the smaller two numbers total the square of the larger number:

  4² +5² = 16 +25 = 41 ≠ 6² . . . . . (4, 5, 6) is not a right triangle

5 0
2 years ago
A particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past
Vadim26 [7]

Answer:

We conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

Step-by-step explanation:

We are given that a particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past studies of this tire, the standard deviation is known to be 8000.

From the 28 tires surveyed, the mean lifespan was 46,500 miles with a standard deviation of 9800 miles.

<u><em>Let </em></u>\mu<u><em> = average miles for deluxe tires</em></u>

So, Null Hypothesis, H_0 : \mu \geq 50,000 miles   {means that deluxe tire averages at least 50,000 miles before it needs to be replaced}

Alternate Hypothesis, H_A : \mu < 50,000 miles    {means that deluxe tire averages less than 50,000 miles before it needs to be replaced}

The test statistics that will be used here is <u>One-sample z test statistics</u> as we know about population standard deviation;

                                  T.S.  = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean lifespan = 46,500 miles

            \sigma = population standard deviation = 8000 miles

            n = sample of tires = 28

So, <u><em>test statistics</em></u>  =  \frac{46,500-50,000}{\frac{8000}{\sqrt{28} } }

                               =  -2.315

The value of the test statistics is -2.315.

Now at 5% significance level, the z table gives critical value of -1.6449 for left-tailed test. Since our test statistics is less than the critical value of z as -2.315 < -1.6449, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

4 0
3 years ago
Solve for x<br>8x - 20 4x + 32​
Alenkinab [10]

Answer:

13

Step-by-step explanation:

8x - 20 = 4x + 32​ ( F rule angles)

8x-4x=32+20

4x=52

x=52/4

x=13

7 0
2 years ago
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