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FinnZ [79.3K]
3 years ago
7

Please help. I can't find answer.

Mathematics
1 answer:
AveGali [126]3 years ago
4 0

Answer:

-1,5

Step-by-step explanation:

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Find an equation of the line satisfying the given conditions Through (6,4); perpendicular to 3X + 5Y =38
Katyanochek1 [597]
To answer this, we will need to know:

• The slope of the equation we are trying to get
• The point it passes through using the 

First, we will need to find the slope of this equation. To find this, we must simplify the equation 3x+5y=38 into y=mx+b form. Lets do it!

3x+5y=38
= 5y = -3x+38 (Subtract 3x from both sides)
= y= -\frac{3}{5}x+ \frac{38}{5} (Divide both sides by 5) 

The slope of a line perpendicular would have to multiply with the equation we just changed to equal -1. In other words, it would have to equal the negative reciprocal.

The negative reciprocal of the line given is \frac{5}{3}. 

Now that we know the slope, we have to find out the rest of the equation using the slope formula, which is:

\frac{y-y _{1} }{x- x_{1} }=m

Substituting values, we find that:

\frac{y-4}{x-6}= \frac{5}{3}

By simplifying this equation to slope-intercept form (By cross-multiplying then simplifying), we then get that: 

y= \frac{5}{3}x-6 , which is our final answer.

Thank you, and I wish you luck.
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If you list all the common factors, (1,2,3,6), you see the highest common factor is 6
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