(6.4 x 10^8 meter/sec) x (1 km / 1,000 meter) x (3,600 sec/hour) =
(6.4 x 10^8 x 3,600 / 1,000) km/hour =
177-7/9 km/hour
Point A is the midpoint of CT which means the ratio of CA:CT would be 1:2.
To find CT, you need to find the distance of CA then applies 2 times of the distance to the point C
Xca= Xa-Xc= 1- (-2)= 3
Yca= Ya- Yc= -3 -5= -8
Xt= Xc + 2* Xca= -2 + 2*3= 4
Yt= Yc + 2* Yca= 5 + 2*-8= -11
T(Xt, Yt)= T(4, -11)
The coordinate for point T would be (4, -11)
The angle from which helicopter take off approximately equals 11.30993247;
6. 7/3
8. 7/3
please don't get mad if these answers are wrong
