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alexdok [17]
2 years ago
15

Help, I don’t understand this DeltaMath question

Mathematics
1 answer:
djyliett [7]2 years ago
7 0
I can use the angle and the length of JH to find the length of IJ.

To do this, I look at the relationship IJ and JH have to the 52 degree angle. JH is opposite to angle I, and IJ is adjacent to angle I. Because the two side lengths are opposite and adjacent, I use the tangent function to solve this.

Tangent of an angle = the length of the opposite side / the length of the adjacent side. This is just another way to say tan(x)=opposite/adjacent

Now I can fill in what I know...
tan(52)=4.2/x
Now, I want to isolate x.
tan(52) = 4.2/x
x(tan(52))=4.2
x=4.2/tan(52)

Now I put 4.2/tan(52) into a calculator and get x = 3.3 ft

Hope this helps!
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PLZZZZZZZZZZZZZZZZZ help
anzhelika [568]

Answer:

true

Step-by-step explanation:

\frac{x}{2}

* substitute 30 for x *

\frac{30}{2}

we're left with 15 < 20 which is true

5 0
2 years ago
Over a two-hour time period, a snail moved 108 inches. How far is this in yards?
kaheart [24]
The snail moved 108 inches
108/36=3 yards
as 1 yard=36 in
5 0
3 years ago
Write the following number in standard decimal form.<br> seven and sixty-one thousandths
amid [387]

Answer:

0.761

Step-by-step explanation:the 7 is in the tenths the 6 is in the hundredths and the 1 is in the thousandths

4 0
2 years ago
Mr. Moretti is making welcome bags to give to the 18 students in his homeroom on the first day of school he puts m mechanical pe
Mashcka [7]

Answer:

The total number of pencils is 6

Step-by-step explanation:

According to the given scenario, the computation of the total number of pencils is as follows:

There are 18 students

And let us assume there is m mechanical pencils that put in each bag

also he put twice of the regular pencil

So if he put the 3 mechanical pencil

So, the total number of pencils is

= 3 × 2

= 6

As it twice of the regular pencil

hence, the  total number of pencils is 6

5 0
2 years ago
Simplify. -10m+2m^4-13m-20m^4
Ulleksa [173]
First one:

you can add -10m and -13m but you can't add -10m and 2m^4 becuase the powers aren't the same so

when adding the like terms
look at the:
powers, (x^3 adds with x^3)
placehloder letter (x adds with x and y adds with y and so on)

-10m+2m^4-13m-20m^4
powers: m^1 and M^4
placeholders: all m


add
-10m-13m+2m^4-20m^4
-23m-18m^4




second one:
when multiplying exponents, you add with like
so if you multipliy
x^2yz^3 times x^4y^2z^2 thne you would get x^6y^3z^5
when multiply with coeficients
2x^2yz^3 times 4x^4y^2z^2=8x^6y^3z^5
so using associative property a(bc)=(ab)c
2/3 times p^4 times y^3 times y^4 times s^5 times 6 times p^2 times s^3
group like terms

(2/3 times 6) times (p^4 times p^2) times (y^3 times y^4) times (s^5 times s^3)
(4) times (p^6) times (y^7) times (s^8)
4p^6y^7s^8

8 0
3 years ago
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