12/20 = 0.6, 10/25 = 0.4 = NO
12/18 =0.66, 10/15 = 0.66 = YES
5/3 = 1.6, 3/5 = 0.6 = NO
8/16 = 0.5, 3/4 =0.75 = NO
Answer is B
Answer: C=2*3.14*r
Step-by-step explanation:
You just plug in 3.14 for pi, it's pretty simple
Answer:
Step-by-step explanation:
(-13u^6 x^6 + 4ux^6) / (-2u^2 x^5) can be rewritten as:
(-13u^6 x^6 + 4ux^6)
-------------------------------
(-2u^2 x^5)
Note that u is common to all terms here. Factoring out u, we get:
(u) [ (-13u^5)(x^6) + 4x^6 ]
--------------------------------------
(u) [-2u (x^5) ]
Reducing this leaves us with:
(-13u^5)(x^6) + 4x^6
--------------------------------------
[-2u (x^5)
Now note that x^5 is common to all terms here. Factoring out x^5, we get:
( -13u^5)(x) + 4x
-------------------------
-2u
This cannot be reduced further, since the 4x term has no u factor.
9514 1404 393
Answer:
1250 square feet
Step-by-step explanation:
If x is the length of the side perpendicular to the creek, then the third side is (100 -2x) = 2(50 -x). The area is the product of length and width:
A = x(2)(50-x)
We observe that this is a quadratic function with zeros at x=0 and x=50. The vertex (maximum) of a quadratic function is on the line of symmetry, halfway between the zeros. The value of x there is (0 +50)/2 = 25.
Then the maximum area is ...
A = (25)(2)(50 -25) = 1250 . . . . square feet
_____
<em>Additional comment</em>
Note that half the length of the fence is used in one direction (parallel to the creek), and half is used in the other direction (perpendicular to the creek). This 50/50 split is the generic solution to all sorts of rectangular corral problems, with or without a creek, with or without internal partitions.
Half the fence is perpendicular to the other half. (If the costs are different in different directions, then the cost is what is split 50/50.)
Answer:
Pls help me in this question
Step-by-step explanation:
Pls help me in this question