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Arada [10]
2 years ago
9

F(x) = 3x³+4x² - 8x - 2

Mathematics
1 answer:
sergij07 [2.7K]2 years ago
4 0

Answer:

does not compute

Step-by-step explanation:

does not compute

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Find the slopes of the asymptotes of the hyperbola with the following equation.
frosja888 [35]
You are given the equation 36 = 9x² + 4y². You are asked to find the slopes of the asymptotes of the hyperbola. A hyperbola has the following general equation x²/a² + y²/b² = 1. the goal here is to find the slopes of the hyperbolic equation. So divide both sides by 36

36 = 9x² + 4y²
(1/36)[36 = 9x² + 4y²]
1 = x²/4 + y²/9
a² = 4
a = 2
and
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To find the slope, divide a/b and you will get 2/3.
3 0
3 years ago
What is seven and one fifth minus four and five eighths?<br> 01 7/8<br> 2 23/40<br> 3 3/8<br> 4 1/4
dalvyx [7]

Answer:

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Step-by-step explanation:

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8 0
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Find the missing side (X) round to the nearest hundredth
nata0808 [166]

Answer:

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Step-by-step explanation:

\displaystyle \frac{x}{11} = csc\:37 \hookrightarrow 11csc\:37 = x \hookrightarrow 18,278041552... = x \\ \\ 18,28 \approx x

<em>OR</em>

\displaystyle \frac{11}{x} = sin\:37 \hookrightarrow xsin\:37 = 11 \hookrightarrow \frac{11}{sin\:37} = x \hookrightarrow 18,278041552... = x \\ \\ 18,28 \approx x

Information on trigonometric ratios

\displaystyle \frac{OPPOCITE}{HYPOTENUSE} = sin\:θ \\ \frac{ADJACENT}{HYPOTENUSE} = cos\:θ \\ \frac{OPPOCITE}{ADJACENT} = tan\:θ \\ \frac{HYPOTENUSE}{ADJACENT} = sec\:θ \\ \frac{HYPOTENUSE}{OPPOCITE} = csc\:θ \\ \frac{ADJACENT}{OPPOCITE} = cot\:θ

I am joyous to assist you at any time.

7 0
2 years ago
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inysia [295]
In the first one put 2. and in the second one put 7 
3 0
3 years ago
Please help me as fast as you can PLEASE
e-lub [12.9K]

Answer:

C

Step-by-step explanation:

6 0
2 years ago
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