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kolezko [41]
2 years ago
8

What coefficient would you get for the x terms on the right side of 3x+15=2x+10+x+5

Mathematics
2 answers:
Zielflug [23.3K]2 years ago
5 0

Answer:

x=0

Step-by-step explanation:

Snezhnost [94]2 years ago
4 0

Answer:

Any real number.

Step-by-step explanation:

3x + 15 = 2x + 10 + x + 5

First, add like terms.

3x + 15 = 3x + 15

Subtract 15 on both sides.

3x = 3x

Divide 3 on both sides.

x = x

Since x equals x, you can give any value (any real number) to x.

Since 3x = 3x, you can say x = 1, meaning 3 = 3.

Or, you can say x = 8. 3x = 3x will be 24 = 24.

x can be any number.

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W=17 im too good at math to be wrong about this
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In triangle QRS, QR = 8 and RS = 5. Which expresses all possible length of side QS?
VLD [36.1K]
Obviously it's answer D) Why?

a) any side of a triangle is SMALLER than the SUM of the 2 others

b) any side of a triangle is GREATER than the DIFFERENCE of the 2 others

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I need help on 12 and 16
krok68 [10]
12. A trapezoid is a quadrilateral. It has 4 sides


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Plz gyz ineed the calculation
postnew [5]

Answer:

1/8

Step-by-step explanation:

1st day......1/3

2nd day....1/6

3rd day....3/8

common denominator of 24

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6 0
3 years ago
Given a minimum usual value of 135.8 and a maximum usual value of 155.9, determine which (1 point) of the following values would
maxonik [38]

Answer:  b. 134

Step-by-step explanation:

Given : A minimum usual value of 135.8 and a maximum usual value of 155.9.

Let x denotes a usual value.

i.e.  135.8< x < 155.9

Therefore , the interval for the usual values is [135.8, 155.9] .

If interval for any usual value is [135.8, 155.9] , then any value should lie in this otherwise we call it unusual.

Let's check all options

a. 137  ,

since  135.8< 137 < 155.9

So , it is usual.

b. 134

since 134<135.8 (Minimum value)

So , it is unusual.

c. 146  

since  135.8< 146 < 155.9

So , it is usual.

d. 155  

since 135.8< 1155 < 155.9

So , it is usual.

Hence, the correct answer is b. 134 .

4 0
3 years ago
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