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3 years ago

I’ll give brainliest if you explain how to do 1 2 and 3:) no links plz!

Mathematics

2 answers:

Nonamiya [84]3 years ago

7 0

Answer:

Step-by-step explanation:

1) $\frac{5}{7}x = 55\\$

Multiply both sides by 7,

$7*\frac{5}{7}x=55*7\\$

$5x = 55 * 7$

Now divide both sides by 5

$\frac{5}{5}x=\frac{55*7}{5}\\\\x = 11*7\\\\x = 77$

ANS: x = 77

2) 6x = 1/5

Divide both sides by 6

$\frac{6}{6}x=\frac{1}{5*6}\\\\x = \frac{1}{30}$

3) 2.17 + x = 5

Subtract 2.17 from both sides

2.17 - 2.17 +x = 5 - 2.17

x = 2.83

$4) \frac{20}{3}=\frac{10}{9}x$

Multiply both sides by 9

$\frac{20}{3}*9=\frac{10}{9}x*9\\\\20*3=10x\\$

Divide both sides by 10

$\frac{20*3}{10}= \frac{10}{10}x\\\\2*3 = x\\\\x = 6$

vovangra [49]3 years ago

3 0

Answer:

5/7 =55

5x/7 =55

7 ⋅ 5x/7 = 7 ⋅ 55

5x = 7⋅ 55

x= 77

1/5/6 = 6x/6

x= 1/30

x+ 2.17 = 5

x+ 2.17 = 5 - 2.17 = 5 - 2.17

x=2.83

Step-by-step explanation:

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Read 2 more answers

If sin theta= - 5/7, which of the following are possible?

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Answer:

$\large\boxed{\sec\theta=\dfrac{7}{\sqrt{24}},\ and\ \tan\theta=-\dfrac{5}{\sqrt{24}}}\\\boxed{\cos\theta=\dfrac{\sqrt{24}}{7},\ and\ \tan\theta=\dfrac{5}{\sqrt{24}}}$

Step-by-step explanation:

$\text{Use:}\\\\\sin^2\theta+\cos^2\theta=1\to\cos\theta=\pm\sqrt{1-\sin^2\theta}\\\\\tan\theta=\dfrac{\sin\theta}{\cos\theta}\\\\\sec\theta=\dfrac{1}{\cos\theta}\\\\==========================\\\\\sin\theta=-\dfrac{5}{7}\\\\\cos\theta=\pm\sqrt{1-\left(-\frac{5}{7}\right)^2}=\pm\sqrt{1-\frac{25}{49}}=\pm\sqrt{\frac{24}{49}}=\pm\dfrac{\sqrt{24}}{\sqrt{49}}=\pm\dfrac{\sqrt{24}}{7}\\\\\sec\theta=\pm\dfrac{1}{\frac{\sqrt{24}}{7}}=\pm\dfrac{7}{\sqrt{24}}$

$\tan\theta=\pm\dfrac{-\frac{5}{7}}{\frac{\sqrt{24}}{7}}=\mp\dfrac{5}{7\!\!\!\!\diagup_1}\cdot\dfrac{7\!\!\!\!\diagup^1}{\sqrt{24}}=\mp\dfrac{5}{\sqrt{24}}$

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