Answer:
Slope = 2
Step-by-step explanation:
(1,3) and (3,7)
m = (7-3)/3-1)
= 4/2
= 2
Answer:
Step-by-step explanation:-16x^2 + 24x + 16 = 0.
A. Divide by 8:
-2x^2 + 3x + 2 = 0, A*C = -2*2 = -4 = -1 * 4. Sum = -1 + 4 = 3 = B, -2x^2 + (-x+4x) + 2 = 0,
(-2x^2-x) + (4x+2) = 0,
-x(2x+1) + 2(2x+1) = 0,
(2x+1)(-x+2) = 0, 2x+1 = 0, X = -1/2. -x+2 = 0, X = 2.
X-intercepts: (-1/2,0), (2,0).
B. Since the coefficient of x^2 is negative, the parabola opens downward. Therefore, the vertex is a maximum.
Locate the vertex: h = Xv = -B/2A = -24/-32 = 3/4, Plug 3/4 into the given Eq to find k(Yv). K = -16(3/4)^2 + 16(3/4) + 16 = 19. V(h,k) = V(3/4,19).
C. Choose 3 points above and below the vertex for graphing. Include the points calculated in part A which shows where the graph crosses the x-axis.
Domain: x² - 4 ≠ 0
+ 4 + 4
x² ≠ 4
√x² ≠ √4
x ≠ ±2
x ≠ -2 and x ≠ 2
(-∞, -2) ∨ (-2, 2) ∨ (2, ∞)
Range: y ≠ 1
(-∞, 1) ∨ (1, ∞)
Intervals: Increasing: (0.25 , ∞)
Decreasing: (-∞, 0.25)
Symmetry: X-axis: Not Symmetric
Y-axis: Not Symmetric
Origin: Not Symmteric
Extrema: Maximum Relative: x = 0
Minimum Relative: Nothing
Answer:
It would be -x
Step-by-step explanation:
when you divide a positive by a negative you get a negative which singles out x.
-1x could be simplified down to just -x which singles out that answer too
<h3>Answer: Choice B) </h3><h3>-6x - 2y = 12</h3>
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Explanation:
The x intercept is (-2,0) which is where the graph crosses the x axis.
The y intercept is (0,-6) which is where the graph crosses the y axis.
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Find the slope of the line through those two points
m = (y2-y1)/(x2-x1)
m = (-6-0)/(0-(-2))
m = (-6-0)/(0+2)
m = -6/2
m = -3
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The y intercept (0,-6) leads to b = -6
Both m = -3 and b = -6 plug into y = mx+b to get
y = mx+b
y = -3x+(-6)
y = -3x-6
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Now add 3x to both sides
y = -3x-6
y+3x = -3x-6+3x
3x+y = -6
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Lastly, multiply both sides by -2 so that the "-6" on the right hand side turns into "12" (each answer choice has 12 on the right hand side)
3x+y = -6
-2(3x+y) = -2(-6)
-2(3x)-2(y) = 12
-6x-2y = 12
which is what choice B shows.
