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2 years ago

11

Image is(-6,-4) what is the pre image

1 answer:

svlad2 [7]2 years ago

8 0

Answer:

In the photo, I want you to look at Graph 1. Look at the bottom left square.

Step-by-Step:

(-6,-4) this problem. For starters, you should know that the first number goes to the bottom. Since we are using negatives, the first cumber goes on top. When you look at the image and see graph 1 in the bottom left square. Notice how it actually shows the replica. Recommend to draw it out yourself. sorry, the image is blurry. <33

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<img src="https://tex.z-dn.net/?f=5%5E%7B-3%7D" id="TexFormula1" title="5^{-3}" alt="5^{-3}" align="absmiddle" class="latex-form

AveGali [126]

Answer:

the equivalent equation of

$5^{-3}$ = $\frac{1}{5^{3}}=\frac{1}{125}$

5 0

2 years ago

Triangles L M N and L K N are connected at side L N. A line is drawn from point M to point K and intersects side L N at point P.

lesya692 [45]

The true statement is Line MK is the perpendicular bisector of LN and ML is ≅ MN.

<h3>What is perpendicular?</h3>

Perpendicular lines are lines that intersect at a right (90 degrees) angle.

Given:

Δ LMN and Δ LKN are connected at side LN.

As per the information,

Line MK is the perpendicular bisector of LN. and ML ≅ MN.

Learn ore about this concept here:

brainly.com/question/25397944

#SPJ1

8 0

1 year ago

Which steps would you use to solve this equation? Check all that apply.

Dovator [93]

Answer: The answers are

Subtract 7 from both sides of the equation.
Subtract 7 from 7.
Substitute 5 for p to check the solution.

Step-by-step explanation:

p + 7 = 12

= p + 7 - 7 = 12 - 7

= p = 5

Then for the substituting part

5 + 7 = 12

Hope this helps!

3 0

3 years ago

Sam rented a truck for one day. There was a base fee of $16.95, and there was an additional charge of 73 cents for each mile dri

Naddik [55]

Answer: 134 miles

Step-by-step explanation:

f(m) = 16.95 + 0.92m

140.23 = 16.95 + 0.92m

0.92m = 140.23 - 16.95

0.92m = 123.28

m = 123.28/0.92

m = 134 miles

5 0

2 years ago

In a missile-testing program, one random variable of interest is the distance between the point at which the missile lands and t

Arisa [49]

Answer:

Step-by-step explanation:

From the given data

we observed that the missile testing program

Y1 and Y2 are variable, they are also independent

We are aware that

$(Y_1)^2 and (Y_2)^2$ have $x^2$ distribution with 1 degree of freedom

and $V=(Y_1^2)+(Y_2)^2$ has x^2 with 2 degree of freedom

$F_v(v)=\frac{e^{-\frac{v}{2}}}2$

Since we have to find the density formula

$U=\sqrt{V}$

We use method of transformation

$h(V)=\sqrt{U}\\\\=U$

There inverse function is $h^-^1(U)=U^2$

We derivate the fuction above with respect to u

$\frac{d}{du} (h^-^1(u))=\frac{d}{du} (u^2)\\\\=2u^2^-^1\\\\=2u$

Therefore,

$F_v(u)=F_v(h-^1)(u)\frac{dh^-^1}{du} \\\\=\frac{e^-\frac{u^-^}{2} }{2} (2u)\\\\=e^-{\frac{u^2}{2} }U$

8 0

3 years ago