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lbvjy [14]
3 years ago
9

Data that's displayed randomly on a scatter plot graph illustrates (please help asap!)

Mathematics
1 answer:
kenny6666 [7]3 years ago
4 0
No correlation = scattered randomly on a pilot graph
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Solve for x in the equation x2 + 4x-4=8.
iren [92.7K]

{x}^{2}  + 4x - 4 = 8 \\  =  >  {x}^{2}  + 4x - 4 - 8 = 0 \\  =  >  {x}^{2}  + 4x - 12 = 0 \\  =  >  {x}^{2}  + 6x  - 2x - 12 = 0 \\  =  >  x(x + 6) - 2(x + 6) = 0 \\  =  > (x - 2)(x + 6) = 0 \\  =  > x = 2 \:  \:  \: or \:  \:  \: x =  - 6

<u>Answer</u><u>:</u>

x = -6 or x = 2

Hope you could get an idea from here.

Doubt clarification - use comment section.

7 0
2 years ago
The gas co2 is diffusin at steady state through a tube 20 cm long having a diameter of 1 cm and containing n2 at 350 k . the tot
Marrrta [24]

The value is J = 1.71*10^-6 kmol/m^2.s

According to the given conditions we get,

The length the tube l= 0.20m

The diameter of the tube d= 0.01m

The total pressure inside the tube P= 101.32kPa

The partial pressure of CO2 at the first end is

P1= 456mm Hg = 60794.832 Pa

The partial pressure of CO2 at the other end is

P2= 76mm Hg = 10132.472 Pa

The temperature is T = 298 K

The diffusion coefficient D= 1.67* 10^-5 m^2/s

Generally the molar flux of CO2 is mathematically represented as

J= D{p1-p2} / R.T

Here R is the gas constant with value R= 8.314 j/kmol

So we get J= 1.71 * 10^-3 mol/m^2.sec

Learn more about Mole on:

brainly.com/question/27270616

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4 0
2 years ago
What is the parent function of the graph?
Alik [6]

Answer:

y = |x| – 4

Step-by-step explanation:

If we substitute x as 0, we get -4 therefore this is the answer.

8 0
3 years ago
Solve for m in the following equation:<br> x = -2kn + m)
Ivenika [448]

Answer:

The answer is m = x + 2kn

Step-by-step explanation:

Rewrite the equation as  − 2 k n  +  m  =  x . Add  2 k n  to both sides of the equation.

8 0
3 years ago
Find two possible factors for the estimate product 2,800
AleksandrR [38]
1,400x2 are two possible factors to estimate the product 2800
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3 years ago
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