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bonufazy [111]
3 years ago
8

Point P is shown graphed on the coordinate grid as (6,4). In relation to point P, point A is located 2 units closer to the origi

n along the x-axis and 2 units farther from it along the y-axis. What would be the location of point A ?
Mathematics
1 answer:
Zina [86]3 years ago
3 0

Answer:

The coordinates of point A are A(x,y) = (4,6).

Step-by-step explanation:

The location of point A is defined by the vectorial sum of absolute coordinates of point P and coordinates of point A relative to coordinates of point P, that is:

A(x,y) = P(x,y) + \vec v_{PA} (1)

P(x,y) - Absolute coordinates of point P.

A(x,y) - Absolute coordinates of point A.

\vec v_{PA} - Vector to point A relative to point P.

If we know that P(x,y) =(6,4) and \vec v_{PA} = (-2, 2 ), then the absolute coordinates of point A are:

A(x,y) = (6,4) +(-2,2)

A(x,y) = (4,6)

The coordinates of point A are A(x,y) = (4,6).

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Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

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Does the set {t, t Int} form a fundamental set of solutions for t^2y" -- ty' +y = 0?
Ivanshal [37]

Answer:

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Step-by-step explanation:

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To find  the solutions are independent or dependent we use wronskain

w(x)=\begin{vmatrix}y_1&y_2\\y'_1&y'_2\end{vmatrix}

If wrosnkian is not equal to zero then solutions are dependent and if wronskian is zero then the set of solution is independent.

Let y_1=t,y_2=t ln t

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3 years ago
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When a complex number is a root of a polynomial function, it's conjugate also has to be.

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The same is valid for radicals, as they are in the \pm format.

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