The equation of a cirecle with radius r and center at (h,k) is
(x-h)^2+(y-k)^2=r^2
r=10
center=(-2,-4)
(x+2)^2+(y+4)^2=10^2
(x+2)^2+(y+4)^2=100
(x,y)
sub given points (or use TI) and see if you get a true statmeent
A is on it
answer is A
Answer:
y=1/5(x+37)
Step-by-step explanation:
y=1/5x+4/5
Plug in the (3,8)
8=1/5(3)+b
8=3/5+b
7 2/5=b
y=1/5(x+37)
Hello,
Please, see the attached file.
Thanks.