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Iteru [2.4K]
3 years ago
10

Can i use some help? im really confused on how to show my work and all

Mathematics
2 answers:
telo118 [61]3 years ago
6 0

Answer:

3/20

Step-by-step explanation:

15% = \dfrac{15}{100}

Divide the numerator and denominator by 5

       = \dfrac{3}{20}

Sidana [21]3 years ago
3 0

Answer:

3/20

15%/100% = 3/20 by dividing top and bottom by 5

15/5=3

100/5 =20

Hope this helps!

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That is a easy one the answer is 8
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What is the slope of a line parallel to the line with equation 5x + 3y = 7?
weeeeeb [17]

Answer:

-5/3

Step-by-step explanation:

Parallel lines are lines which have the exact same slope but different y-intercepts. We can find the slope by converting to slope-intercept form, y=mx+b from standard form.

We convert by using inverse operations to isolate y.

5x+3y=7

5x-5x+3y=7-5x

0x+3y=-5x+7

3y=-5x+7

\frac{3y}{3} =\frac{-5x+7}{3} \\y=\frac{-5}{3}x+\frac{7}{3}.

The slope is -5/3. SInce parallel lines have the same slope, the slope for a parallel line will be -5/3.

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3 years ago
two planes traveling in opposite directions leave the airport at the same time. in 4 hours they are they are 2900 miles apart. i
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Is 1/5 the same as 5?
vesna_86 [32]

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No, it is not.

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3 0
3 years ago
Given that sectheta = -37/12 what is the value of cottheta for pi/2 < theta< pi?
lys-0071 [83]

Answer:

cotg(\theta) = -\frac{12}{35}

Step-by-step explanation:

The cotangent of theta is:

cotg(\theta) = \frac{\cos{\theta}}{\sin{\theta}}

For pi/2 < theta< pi

This means that the angle is in the second quadrant. In the second quadrant, the cosine is negative and the sine is positive. This means that the cotangent will be negative.

Secant:

sec(\theta) = \frac{1}{\cos{\theta}}

In this question

sec(\theta) = -\frac{37}{12}

So

-\frac{37}{12} = \frac{1}{\cos{\theta}}

Using cross multiplication

-37\cos{\theta} = 12

37\cos{\theta} = -12

\cos{\theta} = -\frac{12}{37}

Now we apply the following trigonometric identity:

\sin{\theta}^{2} + \cos{\theta}^{2} = 1

\sin{\theta}^{2} + (-\frac{12}{37})^{2} = 1

\sin{\theta}^{2} = 1 - (-\frac{12}{37})^{2}

\sin{\theta}^{2} = 1 - \frac{144}{1369}

\sin{\theta}^{2} = \frac{1369 - 144}{1369}

\sin{\theta} = \pm \sqrt{\frac{1225}{1369}}

Since the angle is in the second quadrant, the sine is positive.

\sin{\theta} = \frac{35}{37}

Finally, the cotangent:

cotg(\theta) = \frac{\cos{\theta}}{\sin{\theta}}

cotg(\theta) = \frac{-\frac{12}{37}}{\frac{35}{37}}

cotg(\theta) = -\frac{12}{35}

4 0
4 years ago
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