For large sample confidence intervals about the mean you have:
xBar ± z * sx / sqrt(n)
where xBar is the sample mean z is the zscore for having α% of the data in the tails, i.e., P( |Z| > z) = α sx is the sample standard deviation n is the sample size
We need only to concern ourselves with the error term of the CI, In order to find the sample size needed for a confidence interval of a given size.
z * sx / sqrt(n) = width.
so the z-score for the confidence interval of .98 is the value of z such that 0.01 is in each tail of the distribution. z = 2.326348
The equation we need to solve is:
z * sx / sqrt(n) = width
n = (z * sx / width) ^ 2.
n = ( 2.326348 * 6 / 3 ) ^ 2
n = 21.64758
Since n must be integer valued we need to take the ceiling of this solution.
n = 22
Answer:
omgg they literally deleted 10 x 5
Step-by-step explanation:
it's 50, I'll be the calculator fam
Angle needs to sell 16 membership cards.
First, I subtracted 72 from 200 and that gave me 128. Then, I divided 128 by 8 and got 16. To check my work I multiplied 16 by 8 and got 128. Then I added 72 to 128 and got 200.
Hope this helps!
Answer:
Step-by-step explanation:
AC is the geometric mean. Solve it using this proportion:
Now fill in the values we know:
Cross multiply to get
That means that
AC = 
, which, in decimal form is
AC = 11.40175425
For this case we have the following variables:
x: number of bracelets.
C: manufacturing cost
We have then:
C (256) = 1536
Thus,
The number of bracelets is:
256
The price is:
$ 1536
Answer:
the cost to the company is $ 1536 to manufacture 256 braclets
