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3 years ago

Solve by elimination 4x+5y=15 6x-4y=11

Mathematics

1 answer:

lyudmila [28]3 years ago

8 0

X = 5/2 ,y = 1.I usually solve for x first then substitute the answer in one of the equations to find y.

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Vanessa invested $300 in an account for 10 years at 4% simple interest. What is the principal amount?

oksano4ka [1.4K]

Answer:$120

Step-by-step explanation

I had homework over this a day ago

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2 years ago

- 4/7 • (- 3/4) <br> Find the product simplify if possible

Reil [10]

Answer:

I believe the answer is 3/7. Hope this helps!

Step-by-step explanation:

4 0

3 years ago

Coach Evans recorded the height, in inches of each player on his team. The results are shown.

marysya [2.9K]

Answer:

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile $(Q_1)$

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile $(Q_3)$

Terms in arranged in ascending order:

$57,60,60,61,62,62,63,63,64$

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

$Q_1$ is median of terms $57,60,60,61$

Number of terms (n) = 4

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60$

So, $Q_1=60$

So, 25% of the heights of a team is less than 60 inches

$Q_3$ is the median of terms $62,63,63,64$

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63$

So, $Q_3=63$

So, 75% of the heights of a team is less than 63 inches

Interquartile range = $Q_3-Q_1=63-60=3$

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0

3 years ago

Find the value of m .

kondor19780726 [428]

Step-by-step explanation:

if the 2 matrices are inverse, then their product must be the identity matrix

1 0

0 1

so,

m×3 + 2×-7 = 1

7×3 + 3×-7 = 0

m×-2 + 2×m = 0

7×-2 + 3×m = 1

that means we have to solve only

3m - 14 = 1

3m = 15

m = 5

7 0

2 years ago

Here is the assignment : You are "selling" the polynomial. You must convince the buyer you have the Best polynomial on the marke

swat32

Step-by-step explanation:

A polynomial is an expression that can be built from constants and symbols called variables or indeterminates by means of addition, multiplication and exponentiation to a non-negative integer power. Two such expressions that may be transformed, one to the other, by applying the usual properties of commutativity, associativity and distributivity of addition and multiplication, are considered as defining the same polynomial.

A polynomial in a single indeterminate x can always be written (or rewritten) in the form

{\displaystyle a_{n}x^{n}+a_{n-1}x^{n-1}+\dotsb +a_{2}x^{2}+a_{1}x+a_{0},}a_{n}x^{n}+a_{n-1}x^{n-1}+\dotsb +a_{2}x^{2}+a_{1}x+a_{0},

where {\displaystyle a_{0},\ldots ,a_{n}}a_{0},\ldots ,a_{n} are constants and {\displaystyle x}x is the indeterminate.[2][3] The word "indeterminate" means that {\displaystyle x}x represents no particular value, although any value may be substituted for it. The mapping that associates the result of this substitution to the substituted value is a function, called a polynomial function.

This can be expressed more concisely by using summation notation:

{\displaystyle \sum _{k=0}^{n}a_{k}x^{k}}{\displaystyle \sum _{k=0}^{n}a_{k}x^{k}}

That is, a polynomial can either be zero or can be written as the sum of a finite number of non-zero terms. Each term consists of the product of a number – called the coefficient of the term[a] – and a finite number of indeterminates, raised to nonnegative integer

3 0

3 years ago