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anygoal [31]
3 years ago
15

Find the slope of the line containing the points (-3,8) and (-1,0).

Mathematics
1 answer:
Sophie [7]3 years ago
3 0

Answer:

m= -4

Step-by-step explanation:

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A 22 km walk is completed in 5 hours and 30 min.<br> What is the average speed?
Ivenika [448]

Answer:

121 km\hr

Step-by-step explanation:

displacement=speed÷time

then. speed = displacement×time

= 22 × 5.5

= 121 km\hr

4 0
3 years ago
Andrea runs 4 miles every day, but she wants to increase her distance in order to run a 26 mile marathon. She decides to add 2 m
Doss [256]

Answer:

By the time she achieves her 26 mile goal Andrea will have run 176 miles.

Step-by-step explanation:

Since Andrea runs 4 miles every day, but she wants to increase her distance in order to run a 26 mile marathon and she decides to add 2 miles each day to her distance until she achieves her goal, to determine, if she starts with 6 miles today, how many miles will she have run in total, by the time she achieves her 26 mile goal the following calculation should be performed:

6 + 8 + 10 + 12 + 14 + 16 + 18 + 20 + 22 + 24 + 26 = X

14 + 22 + 30 + 38 + 46 + 26 = X

36 + 68 + 72 = X

36 + 140 = X

176 = X

So, by the time she achieves her 26 mile goal Andrea will have run 176 miles.

6 0
3 years ago
I need help from uh all..​
DanielleElmas [232]

Answer:

Step-by-step explanation:

Given expression is,

\text{cot}A=\frac{1}{2}(\text{cot}\frac{A}{2}-\text{tan}\frac{A}{2})

To prove this identity we will take the right side of the identity,

\frac{1}{2}(\text{cot}\frac{A}{2}-\text{tan}\frac{A}{2})=\frac{1}{2}(\frac{1}{\text{tan}\frac{A}{2}}-tan\frac{A}{2})

                         =\frac{1}{2}(\frac{1-\text{tan}^2\frac{A}{2}}{tan\frac{A}{2}})

                         =\frac{1}{2}[\frac{2(1-\text{tan}^2\frac{A}{2})}{2tan\frac{A}{2}}]

                         =\frac{1}{2}(\frac{2}{\text{tan}A} ) [Since \text{tan}A=\frac{2\text{tan}\frac{A}{2}}{1-\text{tan}^2\frac{A}{2}}]

                         = cot A

Hence right side of the equation is equal to the left side of the equation.

3 0
3 years ago
Write the vector v in terms of i and j whose magnitude ||v|| and direction 0 are given. ||v|| = 4, 0 = 315 degree v= (Type your
victus00 [196]

Answer:

  v = 2√2i -2√2j

Step-by-step explanation:

  v = ||v||·cos(θ)i +||v||·sin(θ)j

  v = 4cos(315°)i +4sin(315°)j . . . . . . fill in the numbers

  v = 2√2i -2√2j . . . . . . . . . . . . . . . put in desired form

6 0
3 years ago
Factories <br><img src="https://tex.z-dn.net/?f=8xyz%20-%2010axy" id="TexFormula1" title="8xyz - 10axy" alt="8xyz - 10axy" align
marissa [1.9K]

Answer:

(4z-5a)(2xy)

Step-by-step explanation:

8xyz-10axy

Check for similar terms/like terms

x and y are the same.

The hcf or highest common factor is 2.

The z and a are not common in both terms.

Factor.

8xyz-10axy

2xy(4z-5a)

(4z-5a)(2xy)

8 0
3 years ago
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