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Dimas [21]
4 years ago
6

Father is four times older than his son. In 14 years the father will be twice as old. What are their current ages?

Mathematics
2 answers:
wariber [46]4 years ago
8 0

Answer:

---

Step-by-step explanation:

The son’s age is unknown, so call it: X

The father’s age, four times older, so that means: 4*X= 4X (I use * for multiply)

After 16 years, we add 16 to both ages:

Son: X+16

Father: 4X+16, now, after 16yrs father’s age 2x older than son:

father→ 4X+16 = 2(X+16) = 2X+32 (father twice older than the son age)

4X +16= 2X+32 (after opening the brackets)

4X-2X= 32 - 16 ——-> we moved 2X to left, turned minus -, we moved 16 to the right turned minus -

2X = 16

X = 16/2 = 8

Son’s age is 8 yrs old

Father(Sunil) age is 4x8= 32


After 16 yrs, Father’s age twice older:

8+16=24 (son)

32+16= 48 (Father,Sunil, twice older than son)

Brilliant_brown [7]4 years ago
5 0

Answer:

The son is 7 years old

The father is 28 years old

Step-by-step explanation:

f = fathers age

s = sons age

f = 4s

In 14 years  ( so we add 14 to the age)

f+14 = 2(s+14)

We have 2 equations and 2 unknowns

Replace every f with 4s  (from the first equation)

4s+14 =2(s+14)

Distribute the 2

4s+14 = 2s+28

Subtract 2s from each side

4s-2s+14 = 2s-2s+28

2s+14 = 28

Subtract 14 from each side

2s-14-14 = 28-14

2s = 14

Divide by 2

2s/2 =14/2

s =7

The son is 7 years old

Now lets calculate the fathers age

f =4s

f =4*7

f = 28

The father is 28 years old

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Here's how you simplify those. The rule for raising an exponent to an exponent is that you multiply them. The rule for dividing exponents with the same base is that you subtract the denomonator from the numerator.  So let's simplify the first one, which is actually the most confusing.
( \frac{ p^{5} }{ p^{-3} q^{-4}  } )^{ \frac{1}{4} }
Multiplying the exponents you get:
( \frac{ p^{ \frac{5}{4} } }{ p^{- \frac{3}{4} }  q^{-1} })
Subtracting the denominator from the numerator between the common base of p you get this:
\frac{ p^{ \frac{5}{4}- (-\frac{3}{4})  } }{ q^{-1} }
Doing that math gives you
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The next one:
( \frac{ p^{2} q^{7}  }{ q^{4} } )^{ \frac{1}{2} }
simplifies to:
\frac{p* q^{ \frac{7}{2} } }{ q^{2} }
and subtracting the power of the denominator from the power of the numerator gives you:
p q^{ \frac{3}{2} }, which is the last choice.
( p^{6}q \frac{3}{2})^{ \frac{1}{3} }
simplifies to:
( p^{6* \frac{1}{3} } )( q^{ \frac{3}{2}* \frac{1}{3}  })
which simplifies very nicely to:
p^{2}q^{ \frac{1}{2} }, which is the first choice. The other one is found by process of elimination!
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