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3 years ago

An orange has 30 calories more than a peach

Mathematics

1 answer:

Luden [163]3 years ago

6 0

Answer:

O = p + 30

13p = 7o

O is (x+30)

O = 1+30 ....31

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Due later pls help

Andre45 [30]

Answer:

1. 4z=-8

z= -8/4= -2

2. 2/3t=8/1

2= 24t

t= 0.08

3. 15-1=-8d

14=-8d

d= -1.75

4. 5r-2r=18

3r= 18

r= 6

5. 24= 8y

y=3

6. 3t-3= -t+5

3t+t= 5+3

4t=8

t=2

7. 2x-x= 3+6

x=9

5 0

3 years ago

Which expression is equivalent to n + n - 0.18n

Ket [755]

The correct answer is C) n- 0.18

5 0

4 years ago

Read 2 more answers

Heidi hikes two trails, the Big Trapezoid and the Little Trapezoid. The shorter base of the Big Trapezoid is 2 mi long, while th

Ivenika [448]

If the shapes are similar and the smaller trapezoid's long base is half of the big trapezoid's long base than that means that the small trapezoid's short base would be half of the big trapezoid's short base.

Answer: The Little Trapezoid's shorter base is 1 mi long.

I hope this helps.

8 0

3 years ago

lisa is painting a fence that is 26 feet long and 7 feet tall. a gallon of paint will cover 350 aquare feet. write and slove a p

vaieri [72.5K]

The fence is 26*7=182 square feet. 1 gallon is enough for 350 square feet and x for 182 square feet. => x=182/350=0.52 gallons. I hope I'm right.

4 0

3 years ago

The number of motor vehicles registered in millions in the US has grown as follows:

zysi [14]

Answer:

a) Figure attached

b) $r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}$

For our case we have this:

n=10 $\sum x = 75.819, \sum y = 43.5231, \sum xy = 330.0321, \sum x^2 =574.8598, \sum y^2 =192.8274$

$r=\frac{10(330.0321)-(75.81948)(43.5231)}{\sqrt{[10(574.8598) -(75.819)^2][10(192.8274) -(43.5231)^2]}}=0.989$

So then the correlation coefficient would be r =0.989

Step-by-step explanation:

Previous concepts

The correlation coefficient is a "statistical measure that calculates the strength of the relationship between the relative movements of two variables". It's denoted by r and its always between -1 and 1.

Solution to the problem

Part a

Year (x): 1940, 1945 1950, 1955, 1960, 1965, 1970, 1975, 1980, 1985

Vehicles (Y): 32.4, 31.0, 49.2, 62.7, 73.9, 90.4, 108.4, 132.9, 155.8, 171.7

After apply natural log for the two variables and create the scatterplot in excel we got the following result on the figure attached.

Part b

And in order to calculate the correlation coefficient we can use this formula:

$r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}$

For our case we have this:

n=10 $\sum x = 75.819, \sum y = 43.5231, \sum xy = 330.0321, \sum x^2 =574.8598, \sum y^2 =192.8274$

$r=\frac{10(330.0321)-(75.81948)(43.5231)}{\sqrt{[10(574.8598) -(75.81948)^2][10(192.8274) -(43.5231)^2]}}=0.989$

So then the correlation coefficient would be r =0.989

4 0

3 years ago