Answer:
2x^3-8x^2+8x+12
Step-by-step explanation:
split them up
use distributive property
2x-6(x-2)
2x^2-4x-6x+12(x+1)
use distributive property again
2x^3+2x^2-4x^2-4x-6x^2-6x+12x+12
simplify
2x^3-8x^2+8x+12
I forgot if you can divide it by 2 or not to simplify it even more. If you can, divide it by 2. I forgot the rules
If you divide it by 2, then the answer is
x^3-4x^2+4x+6
Answer:
HHH, W = 3-0 = 3
HHT, W= 2-1=1
HTH, W= 2-1=1
THH, W=2-1 =1
HTT, W= 1-2=-1
THT, W= 1-2=-1
TTH, W=1-2=-1
TTT, W=0-3 = -3
So then the sample space for W is:
![S= [-3,-1,1,3]](https://tex.z-dn.net/?f=%20S%3D%20%5B-3%2C-1%2C1%2C3%5D)
Just 4 possible values from 8 possible combinations for the 3 random tosses
Step-by-step explanation:
For this case we define W as the random variable who represent the number of heads minus the number of tails in three tosses of a coin.
W= # heads- # coins
Since we toss a coin 3 times we have 2*2*2= 8 possible results. We can list the results and the corresponding values for W like this:
HHH, W = 3-0 = 3
HHT, W= 2-1=1
HTH, W= 2-1=1
THH, W=2-1 =1
HTT, W= 1-2=-1
THT, W= 1-2=-1
TTH, W=1-2=-1
TTT, W=0-3 = -3
So then the sample space for W is:
![S= [-3,-1,1,3]](https://tex.z-dn.net/?f=%20S%3D%20%5B-3%2C-1%2C1%2C3%5D)
Just 4 possible values from 8 possible combinations for the 3 random tosses
Answer:
Step-by-step explanation:
Let's look at the first two, and hopefully you'll be able to figure the rest out:
1. Answer below

The problem asks us to solve for
, so that means we need to get
on one side of the equation by itself. To do so, we will need to divide both sides of the equation by
:


2. Answer below

The problem asks us to solve for
, so that means we need to get
on one side of the equation by itself. To do so, we will need to add
to both sides of equation:


Answer:
no not really
Step-by-step explanation:
the values dont match up
Number 6 and 7 are incorrect and I can't read 1/2/3
for 6
7/10 would be 70%
for 7
3 2/5 would be 3.40 not 3.25