The polygons are similar. The area of one polygon is given. Find the area of the other polygon.
2 answers:
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Answer:
The values of variables x and m are 11 and 17
Step-by-step explanation:
The question has missing details as the diagram of the trapezoid isn't attached.
(See attachment).
Given that trapezoid CHLE is isosceles then the angles at the base area equal (4x)
And
The angles at the top are also equal
8m = 11x + 15
At this point, the four angles in the trapezoid are 8m, 11x + 15, 4x and 4x..
The sum of interior= 360
So,
11x + 15 + 8m + 4x + 4x = 360
Collect like terms
11x + 4x + 4x + 8m = 360 - 15
19x + 8m = 345
Substitute 11x + 15 for 8m
19x + 11x + 15 = 345
30x + 15 = 345
30x = 345 - 15
30x = 330
Divide through by 30
30x/30 = 330/30
x = 11
Recall that 8m = 11x + 15;
8m = 11(11) + 15
8m = 121 + 15
8m = 136
Divide through by 8
8m/8 = 136/8
m = 17
Hence, the values of variables x and m are 11 and 17
