You need to take the whole function of g(x) and plug it into every single x within f(x). Bit tricky, so it just means we need to be careful. Alright, so this is the first set-up<span><span><span><span>−2x−7</span><span>x−1</span></span>−7</span><span><span><span>−2x−7</span><span>x−1</span></span>+2</span></span>So what You should do is make the top portion and the bottom portion all into one fraction. This means I need a common denominator. So to do this, I'll take x-1 as a common denominator and multiply it up into the numerator and the imaginary 1 denominator of -7 and 2. Doing this I have:<span><span><span>−2x−7−7(x−1)</span><span>x−1</span></span><span><span>−2x−7+2(x−1)</span><span>x−1</span></span></span>From here if I divide the top fraction and the bottom fraction, (x-1) will cancel out dueto me flipping the bottom fraction and multiplying. So that leaves me with:<span><span>−2x−7−7(x−1)</span><span>−2x−7+2(x−1)</span></span>Now if I multiply everything out and combine like terms I will have:<span><span><span>−2x−7−7x+7</span><span>−2x−7+2x−2</span></span>=<span><span>−9x</span><span>−9</span></span>=x</span>So that is the first part. We have to check both ways to confirm they are actually inverses of each other, though. Take a look at this part and see if you can make sense of what I did.
Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
Slide 1:
A) (x+2)(x+8)
B) (x+3)(x+4)
C) (x+1)(x+12)
Slide 2:
A) (x-1)(x+4)
B) (x+1)(x-3)
C) (x-2)(x+4)
Hope this helps!
Square roots are numbers.
if you multiply a number by itself then it is a square number. if you are looking to find a square root of a number, a square root is finding the number that was squared (multiplied by itself) to make the other number. For example,
the square root of 4 = 2
2×2 =4
Another example, square root of 64 is 8
8×8 is 64 :)
