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fgiga [73]
3 years ago
15

F(t) = 3t^3 - 4t + 6t^2 and g(n) = 5t^3 + 2t^2 - 3t. What is f(t) - g(t)

Mathematics
1 answer:
nikdorinn [45]3 years ago
3 0

Answer:

- 2t³ + 4t² - t

Step-by-step explanation:

f(t) - g(t)

= 3t³ - 4t + 6t² - (5t³ + 2t² - 3t) ← distribute parenthesis by - 1

= 3t³ - 4t + 6t² - 5t³ - 2t² + 3t ← collect like terms

= - 2t³ + 4t² - t

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It says solution to the equation as a decimal q-1.8+1.8=14+1.8
Zielflug [23.3K]
Q-1.8+1.8=14+1.8= Q=15.8 hope this helps
6 0
3 years ago
A bank is investigating ways to entice customers to charge more on their credit cards. (Banks earn a fee from the merchant on ea
MAVERICK [17]

Answer:

CI = (\bar{x_{1} } - \bar{x_{2}} ) \pm MoE\\\\

CI = (527 - 439) \pm 25.75\\\\CI = 88 \pm 25.75\\\\CI = 88 - 25.75 \:\: and \:\: 88 + 25.75\\\\CI = (62.2 \: ,\: 113.8 )

The correct answer choice is a. (62.2, 113.8)

Step-by-step explanation:

Of the 500 customers who were told the increase applied to charges above $1000 each month, the average increase in spending was $527 with a standard deviation of $225.

Sample size = n₁ = 500

Sample mean = x₁ = $527

Standard deviation = s₁ = $225

Of the 500 customers who were told the increase applied to charges above $2000 each month, the average increase in spending was $439 with a standard deviation of $189

Sample size = n₂ = 500

Sample mean = x₂ = $439

Standard deviation = s₂ = $189

We are asked to find the 95% confidence interval for the difference between two means.

The given group of answer choices are

a. (62.2, 113.8)

b. (86.2, 120.5)

c. (10.3, 23.8)

d. (55.6, 67.8)

The confidence interval for the difference between two means is given by

CI = (\bar{x_{1} } - \bar{x_{2}} ) \pm MoE\\\\

Where \bar{x_{1} } and \bar{x_{2} } are the given sample means and margin of error is given by

$ MoE = z_{\alpha/2} \cdot \sqrt{\frac{s_{1}^2}{n_1} + \frac{s_{2}^2}{n_2}} $

The z-score corresponding to 95% confidence level is given by

Significance level = α = 1 - 0.95 = 0.05/2 = 0.025

From the z-table at α = 0.025 the z-score is 1.96

$ MoE = 1.96 \cdot \sqrt{\frac{225^2}{500} + \frac{189^2}{500}} $

MoE = 1.96 \cdot 13.14

MoE = 25.75

Finally,

CI = (\bar{x_{1} } - \bar{x_{2}} ) \pm MoE\\\\

CI = (527 - 439) \pm 25.75\\\\CI = 88 \pm 25.75\\\\CI = 88 - 25.75 \:\: and \:\: 88 + 25.75\\\\CI = (62.2 \: ,\: 113.8 )

Therefore, the correct answer choice is a. (62.2, 113.8)

How to use z-table?

In the z-table find the probability of 0.025

Note down the value of that row, it would be 1.9.

Note down the value of that column, it would be 0.06.

Add the two numbers together.

The z-score is 1.9 + 0.06 = 1.96

4 0
4 years ago
I have this same problem in math but with different wording. I thought it would be funnier to show this one though xD but pls he
Sever21 [200]
Wish I could help. If you give me the real problem I will help you.
5 0
3 years ago
Ramon and justine are both watching brodcast both star at 7:00 a.M and ends at 9:00 a.M one one shows commercials every 17 minut
hoa [83]

Answer:

<h2>1:58 minutes after the show</h2>

Step-by-step explanation:

Step one:;

given data

start time= 7:00 am

end time= 9:00 am

we are told that one broadcast shows commercial every 17minutes

and the other shows commercials every 14 minutes

now the time when they both sho commercial is given by the greates common multiple of the times 17 and 14

multiples of  17= 17,34,51,68,85,102,119,136,153,170,187,204,221,238

multiples of  14= 14,28,42,56,70,84,98,112,126,140,154,168,182,196,210,224,238

for the number above 238 is common to both

238minutes to hours= 3.96667

=3:58 minutes

this shows that commercials will show at the same time 1:58 minutes after the show

4 0
3 years ago
Evaluate 5 - (4 + 2)2<br> O A. 9<br> O B. -15<br> O C. 5<br> O D.-31
solong [7]

Answer:

exponents first then multiply and subtract after

Step-by-step explanation:

the answer is 5

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