Answer:Pois(ln(200))
Step-byy-step explanation:
Let N be the number of received calls in a day
That is
N∼Pois(λ).
0.5% = 0.5/100 = 1/200 of no calls
P(N=0)=e^−λ=1/200
-λ=e^(1/200)
λ=in(200)
Our number of calls in a day is distributed Pois(ln(200)).
Your answer is : B hope this helps
Answer:
x = 0
Step-by-step explanation:
Answer:

Step-by-step explanation:
-The locust population grows by a factor and can therefore be modeled by an exponential function of the form:

Where:
is the population after t days.
is the initial population given as 7600
is the rate of growth
is time in days
-Given that the growth is by a factor of 5( equivalent to 500%), the r value will be 5
-The population increases by a factor of 5 every 22 days. therefore at any time instance, t will be divided by 22 to get the effective time for calculations.
Hence, the exponential growth function will be expressed as:

Answer:
Half of 24 is 12
Step-by-step explanation:
24/2 = 12