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alexdok [17]
3 years ago
7

MA + q ² A =g Someone help me to do this Aquarian

Mathematics
1 answer:
Fed [463]3 years ago
8 0

Answer:

a=g/q2+m

Step-by-step explanation:Let's solve for a.

ma+q2a=g

Step 1: Factor out variable a.

a(q2+m)=g

Step 2: Divide both sides by q^2+m.

a(q2+m)

q2+m

=

g

q2+m

a=

g

q2+m

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9/16, 0.25, 5/48, 0.5 least from greatest
zubka84 [21]

Answer:

9/16, 0.5, 0.25, 5/48

Step-by-step explanation:

hope this helps

4 0
3 years ago
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The probability of winning the shell games if you
mart [117]
A.) 33.3% _
1 divided by 3 = 0.3 and if you multiply it by 100 it equals 33.3%
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3 years ago
Alicia is writing the program for a video game. For one part of the game, she uses the rule
astra-53 [7]

As the mapping suggests, the first (x) coordinate is decreased by 3, and the second (y) coordinate is increased by 2. So, given the inputs, you have

(-2,0) \mapsto (-2-3, 0+2) = (-5,2)

(3,-4) \mapsto (3-3, -4+2) = (0,-2)

And yes, this rule is a function: it has a starting set (the domain), which is all possible couples (x,y), and a landing set (the codomain), which is again composed by the couples (x,y). Since for every point in the domain you have one and only one output, this rule is a function.

7 0
4 years ago
What is the solution to the system of equations?
irina [24]

Answer:

The solution is the point (6,-8)

Step-by-step explanation:

we have that

The first equation is y=(1/3)x-10 instead y=x-10

y=(1/3)x-10 -----> equation A

2x+y=4 -----> equation B

Solve the system of equations by substitution

Substitute equation A in equation B and solve for x

2x+[(1/3)x-10]=4

(7/3)x=14

x=6

Find the value of y

y=(1/3)(6)-10=-8

therefore

The solution is the point (6,-8)

4 0
4 years ago
During a school tournament, Team A had 10 of its 12 team members present.
jonny [76]

Answer:

Team A.

Step-by-step explanation:

We know that Team A had 10 of its 12 members present.

We can write this as the following fraction:

A=10/12

We can convert this to a decimal by dividing the two numbers. Use a calculator:

A\approx.8333

And we can convert this to a percent by moving the decimal too places to the right and by adding a percent sign:

A\approx83.33\%

So, about 83.33% of members on Team A was present.

We know that Team B had 13 of its 15 members present.

We can write this as the following fraction:

B=13/15

Again, we can convert this to a decimal by dividing the two numbers:

B\approx 0.8667

Change this to a percent:

B\approx86.67\%

So, Team A had a participation rate of 83.33% while Team B had a participation rate of 86.67%.

So, the team that had the lesser percent of the team present at the tournament is Team A.

And we're done!

6 0
3 years ago
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